程序師世界是廣大編程愛好者互助、分享、學習的平台,程序師世界有你更精彩!
首頁
編程語言
C語言|JAVA編程
Python編程
網頁編程
ASP編程|PHP編程
JSP編程
數據庫知識
MYSQL數據庫|SqlServer數據庫
Oracle數據庫|DB2數據庫
 程式師世界 >> 編程語言 >> C語言 >> C++ >> 關於C++ >> [LeetCode]91.Decode Ways

[LeetCode]91.Decode Ways

編輯:關於C++

題目

A message containing letters from A-Z is being encoded to numbers using the following mapping:

‘A’ -> 1
‘B’ -> 2

‘Z’ -> 26
Given an encoded message containing digits, determine the total number of ways to decode it.

For example,
Given encoded message “12”, it could be decoded as “AB” (1 2) or “L” (12).

The number of ways decoding “12” is 2.

分析

這裡寫圖片描述

代碼

/*---------------------------------------
*   日期:2015-06-23
*   作者:SJF0115
*   題目: 91.Decode Ways
*   網址:https://leetcode.com/problems/decode-ways/
*   結果:AC
*   來源:LeetCode
*   博客:
-----------------------------------------*/
#include 
using namespace std;

class Solution {
public:
    int numDecodings(string s) {
        int size = s.size();
        if(s[0] == '0'){
            return 0;
        }//if
        if(size == 0 || size == 1){
            return size;
        }//if
        int pre = 1,cur = 1,res;
        for(int i = 1;i < size;++i){
            if(isValid(s[i-1],s[i]) && isValid(s[i])){
                res = pre + cur;
            }//if
            else if(!isValid(s[i-1],s[i]) && isValid(s[i])){
                res = cur;
            }//else
            else if(isValid(s[i-1],s[i]) && !isValid(s[i])){
                res = pre;
            }//else
            else{
                return 0;
            }//else
            pre = cur;
            cur = res;
        }//for
        return res;
    }
private:
    bool isValid(char pre,char cur){
        if(pre == '1' || (pre == '2' && cur <= '6')){
            return true;
        }//if
        return false;
    }
    bool isValid(char cur){
        if(cur >= '1' && cur <= '9'){
            return true;
        }//if
        return false;
    }
};

int main(){
    Solution s;
    string str("1202111110");
    cout<

運行時間

這裡寫圖片描述

思路2–超時

/*---------------------------------------
*   日期:2015-06-21
*   作者:SJF0115
*   題目: 91.Decode Ways
*   網址:https://leetcode.com/problems/decode-ways/
*   結果:超時
*   來源:LeetCode
*   博客:
-----------------------------------------*/
#include 
using namespace std;

class Solution {
public:
    int numDecodings(string s) {
        int size = s.size();
        if(size == 0 || size == 1){
            return size;
        }//if
        int index = -1;
        int count = 0;
        helper(s,index,count,"");
        return count;
    }
private:
    void helper(string &s,int index,int &count,string word){
        int size = s.size();
        if(index == size-1){
            ++count;
            cout<<"word->"< 0){
                    word += ('A'+num-1);
                    helper(s,index+i,count,word);
                    word.erase(word.size()-1);
                }//if
                else{
                    break;
                }
            }//if
        }//for
    }
};

int main(){
    Solution s;
    string str("1234");
    cout<
  1. 上一頁:
  2. 下一頁:
Copyright © 程式師世界 All Rights Reserved