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 程式師世界 >> 編程語言 >> 更多編程語言 >> 編程綜合問答 >> unity3-unity c#中為什麼不能直接更改transform.position.x的值?

unity3-unity c#中為什麼不能直接更改transform.position.x的值?

編輯:編程綜合問答
unity c#中為什麼不能直接更改transform.position.x的值?

The reason you can't directly alter the position vector is because it's actually a copy, not the actual position stored on the transform.

transform.position <--- returns a copy of the position
transform.position.x <--- the "x" value of the copy
transform.position.x = 7.0f <--- sets the "x" value on the copy

C# throws an error because you're setting the "x" value on a copy, which is then destroyed. It's a pointless line that if the compiler didn't pick up on it, could cause a tonne of hair pulling.

UnityScript gets around this when it compiles by converting your code and firing the C# setter:
transform.position.x = 7.0f
when compiled in UnityScript, translates (more or less) to:
var tempVector : Vector3 = transform.position;
tempVector.x = 7.0f;
transform.position = tempVector;

You can infer that because if you replicate this with a custom C# class, you can track as the getters/setters are invoked.

權威資料是這樣解釋的。這個如何解釋,transform.position(position是Vector3類型的),transform是類。vector3是結構體的,vector3創建的可以直接修改x值,為什麼這個position.x就不可以,實在不明白了?

最佳回答:


找到方法了,不是開放那邊的定的

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