PROBLEM:
[email protected] (Andrew J. Jackson)
I'm inquiring on how to declare a reference to an array of integers
RESPONS: Efim Birger (
[email protected])
try this:
typedef int *intp;
int arr[10];
intp& aaa = arr;
RESPONSE:
[email protected] (Fergus Henderson), 11 Aug 94
This code is illegal. `aaa' is a (non-const) reference to a pointer to int.
`arr' is an array of int, which will be converted to a pointer to int.
The result of that conversion is a temporary.
You are initializing a non-const reference with a temporary, which is illegal.
RESPONSE:
[email protected] (Bernd Eggink)
There is no sUCh thing as a reference to an array.
RESPONSE:
[email protected] (Fergus Henderson)
There most certainly is.
(An array of references is illegal, but a reference to an array is quite OK.)
