hdu 1076 An Easy Task

Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 19908Accepted Submission(s): 12725


Problem Description Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

Input The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).

Output For each test case, you should output the Nth leap year from year Y.

Sample Input

3 2005 25 1855 12 2004 10000
Sample Output

2108 1904 43236 Hint We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.
Author Ignatius.L

 

Y 開始以後的第N個閏年

閏年為能被4整除不能被100整除 或者被400整除

 

#include 
int main()
{
	int ncase;
	scanf("%d",&ncase);
	while(ncase--)
	{
		int year,n;
		scanf("%d %d",&year,&n);
		for(int i=year;;i++)
		{
			if((i%4==0&&i%100)||i%400==0)
			n--;
			if(n==0)
			{
				printf("%d\n",i);
				break;
			}
		}
	}
	return 0;
}