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 程式師世界 >> 編程語言 >> C語言 >> C++ >> C++入門知識 >> C/C++ 2D數組的動態分配方法比較

C/C++ 2D數組的動態分配方法比較

編輯:C++入門知識

方法1:
 1 #include <iostream>
 2 using namespace std;
 3
 4 //by snape 2012-3-25
 5 //method 1: drawback is we need calculate the one-dimensional index to access the 2D array
 6 int main()
 7 {
 8     int rowSize, colSize, totalSize;
 9     int index, i,j;
10
11     cout<<"Enter the row and column size for your 2D array!"<<endl;
12     cin>>rowSize>>colSize;
13
14     totalSize=rowSize*colSize;
15     int *pArray;
16     pArray=new int[totalSize];
17
18     //file  the array with integers from 0 to totalsize
19     //file across the rows, moving down the colums
20
21     int arrayValue=0;
22     for(i=0; i<rowSize; ++i)    //outer-loop traverse down the "rows"
23     {
24         for(j=0; j<colSize; ++j)
25         {
26             //caculate array index
27             //index=rowSize*j+i;        //both index=rowSize*j+i; and index=colSize*i+j; are ok
28             index=colSize*i+j;            //but if index=rowsize*i+j; or index=colSize*j+i; then there will be a bug.
29             pArray[index]=arrayValue;    // i like index=colSize*i+j; since the arrange of 2D is according to rows
30             cout<<"index="<<index<<endl;
31             cout<<"i(row)="<<i<<"j(col)="<<j<<"array value"<<pArray[index]<<endl;
32             ++arrayValue;
33         }
34     }
35
36     //output the array
37     for(int k=0; k<totalSize; ++k)
38     {
39         cout<<pArray[k]<<endl;
40     }
41     cout<<"The End"<<endl;
42     delete [] pArray;
43     return 0;
44 }
45
46

方法2:
 1 //by snape
 2 //method 2: better than method 1, but call new twice
 3 int main()
 4 {
 5     int rowSize, colSize, totalSize;
 6     int i, j;
 7     cout<<"Enter the row and column size for your 2D array"<<endl;
 8     cin>>rowSize>>colSize;
 9
10     totalSize=rowSize*colSize;
11
12     int *pArray; //pointer to an integer
13     int **pPointerArray; //pointer to an integer pointer
14
15     pArray=new int[totalSize];    //memory for totalSize integers
16     pPointerArray=new int*[rowSize];    //memory for rowSize # of int pointers
17
18     //fill the pointer array with the pArray[i][0] address
19     for(i=0; i<rowSize; ++i)
20         pPointerArray[i]=pArray+i*colSize;    //place the address into the pointer
21
22     //now fill the pArray by using the pPointerArray to access elements
23     int arrayValue=0;
24     for(i=0; i<rowSize; ++i)
25     {
26         for(j=0; j<colSize; ++j)
27         {
28             pPointerArray[i][j]=arrayValue;    //cool
29             cout<<"i(row)="<<i<<"j(col)="<<j<<"array value="<<pPointerArray[i][j]<<endl;
30             ++arrayValue;
31         }
32     }
33
34         //output the array
35     for(int k=0; k<totalSize; ++k)
36     {
37         cout<<pArray[k]<<endl;
38     }
39     cout<<"The End!"<<endl;
40     delete [] pArray;
41     delete [] pPointerArray;
42     return 0;
43 }

方法3:
 1 // by snape
 2 //method 3: better than method 2. just malloc once and the memory is contiguous block. the best
 3 int **my2DAlloc(int rowSize, int colSize)
 4 {
 5     int i;
 6     int header=rowSize * sizeof(int *);
 7     int data=rowSize * colSize * sizeof(int);
 8     int **rowptr=(int **)malloc(header+data);    //malloc memory for both data and pointerArray(the header)
 9
10     if(rowptr==NULL)
11         return NULL;
12     int *buf=(int *)(rowptr+rowSize);    //buf: the pointer to the first data
13     for(i=0; i<rowSize; ++i)    //assign the address of each row to pointerArray(the header)
14         rowptr[i]=buf+i*colSize;
15
16     return rowptr;
17 }
18
19 int main()
20 {
21     cout<<"Enter the row and column size for your 2D array"<<endl;
22     int rowSize, colSize;
23     cin>>rowSize>>colSize;
24     int **p=my2DAlloc(rowSize, colSize);
25
26     //assign values
27     int i, j, arrayValue=0;
28     for(i=0; i<rowSize; ++i)
29         for(j=0; j<colSize; ++j)
30             p[i][j]=arrayValue++;
31    
32     //output values
33     for(i=0; i<rowSize; ++i)
34         for(j=0; j<colSize; ++j)
35             cout<<p[i][j]<<endl;
36
37     free((void *)p);
38 }

方法3,我感覺最好,只調用一次malloc, 空間連續,釋放內存也比較方便。

大家有什麼想法的歡迎交流

 

摘自  chenglong7997 

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