面試題:輸入數值n,打印從1到最大的n位數,例如輸入n=3,則從1,2,3,一直打印到999 該題會考查大整數的加法,我之前做大整數運算時,為了圖方便,用整數數組來表示,但這會浪費空間,這次我用字符數組來表示,並且存數的時候是按正常順序來存取 在判斷是否到達上限時,通過判斷最高位是否需要做進位運算來判斷,具體代碼如下:
#include <iostream>
#include <string.h>
#include <fstream>
#include <stack>
#include <exception>
using namespace std;
void print(char *num,int n)
{
bool shouldStart=false;
for(int index=0;index<n;index++)
{
if(!shouldStart && num[index]!='0')
{
shouldStart=true;
}
if(shouldStart)
{
cout<<num[index];
}
}
cout<<endl;
}
bool incNum(char *num,int n)
{
bool overFlow=false;
int carryBit=0;
for(int index=n-1;index>=0;index--)
{
int sum=num[index]-'0'+carryBit;
if(index==n-1)
{
sum++;
}
if(sum>=10)
{
if(index==0)
{
overFlow=true;
}else
{
sum=sum%10;
carryBit=1;
num[index]=sum+'0';
}
}else
{
carryBit=0;
num[index]=sum+'0';
break;
}
}
return overFlow;
}
void printAllNum(int n)
{
if(n<=0)
{
//throw new exception("the input is error");
}
char *num=new char[n+1];
memset(num, '0', n);
num[n]='\0';
while(!incNum(num,n))
{
print(num,n);
}
delete []num;
}
int main()
{
int n;
cin>>n;
printAllNum(n);
//getchar();
return 0;
}
#include <iostream>
#include <string.h>
#include <fstream>
#include <stack>
#include <exception>
using namespace std;
void print(char *num,int n)
{
bool shouldStart=false;
for(int index=0;index<n;index++)
{
if(!shouldStart && num[index]!='0')
{
shouldStart=true;
}
if(shouldStart)
{
cout<<num[index];
}
}
cout<<endl;
}
bool incNum(char *num,int n)
{
bool overFlow=false;
int carryBit=0;
for(int index=n-1;index>=0;index--)
{
int sum=num[index]-'0'+carryBit;
if(index==n-1)
{
sum++;
}
if(sum>=10)
{
if(index==0)
{
overFlow=true;
}else
{
sum=sum%10;
carryBit=1;
num[index]=sum+'0';
}
}else
{
carryBit=0;
num[index]=sum+'0';
break;
}
}
return overFlow;
}
void printAllNum(int n)
{
if(n<=0)
{
//throw new exception("the input is error");
}
char *num=new char[n+1];
memset(num, '0', n);
num[n]='\0';
while(!incNum(num,n))
{
print(num,n);
}
delete []num;
}
int main()
{
int n;
cin>>n;
printAllNum(n);
//getchar();
return 0;
}
第二種解法 n位數相當於對做個全排列,在輸出時,把前導的0去掉,就會輸出正確結果
#include <iostream>
#include <string.h>
#include <fstream>
//#include <stack>
//#include <exception>
using namespace std;
void printFinal(char *num,int n)
{
bool shouldStart=false;
for(int index=0;index<n;index++)
{
if(!shouldStart && num[index]!='0')
{
shouldStart=true;
}
if(shouldStart)
{
cout<<num[index];
}
}
if(shouldStart)
{
cout<<endl;
}
}
void print(char *num, int n,int start)
{
if(start==n)
{
printFinal(num,n);
return;
}
for(int val=0;val<10;val++)
{
num[start]=val+'0';
print(num,n,start+1);
}
}
void printAllNum(int n)
{
if(n<=0)
{
//throw new exception("the input is error");
}
char *num=new char[n+1];
memset(num, '0', n);
num[n]='\0';
print(num,n,0);
}
int main()
{
int n;
cin>>n;
printAllNum(n);
//getchar();
return 0;
}
#include <iostream>
#include <string.h>
#include <fstream>
//#include <stack>
//#include <exception>
using namespace std;
void printFinal(char *num,int n)
{
bool shouldStart=false;
for(int index=0;index<n;index++)
{
if(!shouldStart && num[index]!='0')
{
shouldStart=true;
}
if(shouldStart)
{
cout<<num[index];
}
}
if(shouldStart)
{
cout<<endl;
}
}
void print(char *num, int n,int start)
{
if(start==n)
{
printFinal(num,n);
return;
}
for(int val=0;val<10;val++)
{
num[start]=val+'0';
print(num,n,start+1);
}
}
void printAllNum(int n)
{
if(n<=0)
{
//throw new exception("the input is error");
}
char *num=new char[n+1];
memset(num, '0', n);
num[n]='\0';
print(num,n,0);
}
int main()
{
int n;
cin>>n;
printAllNum(n);
//getchar();
return 0;
}