C說話應用通俗輪回辦法和遞歸求斐波那契序列示例代碼

C說話應用通俗輪回辦法和遞歸求斐波那契序列示例代碼。本站提示廣大學習愛好者：（C說話應用通俗輪回辦法和遞歸求斐波那契序列示例代碼）文章只能為提供參考，不一定能成為您想要的結果。以下是C說話應用通俗輪回辦法和遞歸求斐波那契序列示例代碼正文

#include <stdio.h>

int fac(int x);

int main(void)
{
    int n;
    scanf("%d", &n);
    if (n == 1 || n == 2)
        printf("1\n");
    else if (n == 3)
        printf("2\n");
    else
    {
        int last = 1;
        int sum = 2;
        for (int i = 3; i < n; ++i)
        {
            int temp = sum;
            sum = sum + last;
            last = temp;
        }
        printf("輪回求出斐波那契序列值:%d\n", sum);
    }
    int sum2 = fac(n);
    printf("遞歸求出斐波那契序列值:%d\n", sum2);
    return 0;
}

//遞歸

int fac(int x)
{
   static int f[50] = {1,1};

   if (x == 1 || x == 2)
      return f[x-1];

   return f[x-1] == 0 ?
          ( f[x-1] = fac(x-1) + fac(x-2) ) :
          f[x-1] ;
}