輸入三邊判斷是否能組成三角形

從鍵盤輸入三個整數a、b、c，(1<=a、b、c<=100)

判斷是否構成三角形，若能構成三角形，指出構成的是

等邊三角形？等腰三角形？不等邊三角形？

判斷能否組成三角形的條件為：是否三邊都滿足兩邊之和大於第三邊。

#include <iostream>
using namespace std;
class triangle{
    private:
        float edge_a;
        float edge_b;
        float edge_c;
        bool compare();
    public:
        triangle(){
            edge_a = 0.0;
            edge_b = 0.0;
            edge_c = 0.0;
        }
        triangle(float a, float b, float c){
            edge_a = a;
            edge_b = b;
            edge_c = c;
        }
        int isTriangle();
        int whatTriangle();
                                   
};
bool triangle::compare(){
    if (edge_a+edge_b>edge_c && edge_b+edge_c>edge_a && edge_c+edge_a>edge_b)
        return true;
    else   
        return false;
}
int triangle::isTriangle(){
    if (this->compare()){
        return this->whatTriangle();
    }
    else
        return 0;
}
int triangle::whatTriangle(){
    if (edge_a == edge_b && edge_b == edge_c && edge_c == edge_a)
        return 1;
    else if (edge_a == edge_b || edge_b == edge_c || edge_c == edge_a)
        return 2;
    else
        return 3;
}
int main(){
    int a,b,c;
    int choice=1;
    while (choice)
    {
        system("cls");
        cout<<"請輸入三角形的三邊邊長。"<<endl;
        cout<<"a=";
        cin>>a;
        cout<<"b=";
        cin>>b;
        cout<<"c=";
        cin>>c;
        triangle tri(a,b,c);
        int result = tri.isTriangle();
        switch (result)
        {
            case 1:
                cout<<"可以組成等邊三角形。";
                break;
            case 2:
                cout<<"可以組成等腰三角形。";
                break;
            case 3:
                cout<<"可以組成不等邊三角形。";
                break;
            default:
                cout<<"無法組成三角形。";
        }
        cout<<endl;
        cout<<"要繼續請輸入1，要退出請輸出0."<<endl;
        cin>>choice;
    }  
    cout<<"退出程序."<<endl;
    return 0;
}

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本文出自 “淡定的dreamer” 博客，請務必保留此出處http://idiotxl1020.blog.51cto.com/6419277/1290434