建議57:實現ISerializable的子類型應負責父類的序列化
我們將要實現的繼承自ISerializable的類型Employee有一個父類Person,假設Person沒有實現序列化,而現在子類Employee卻需要滿足序列化的場景。不過序列化器並沒有默認處理Person類型對象,這些事情只能由我們自己做。
以下是一個不妥的實現,序列化器只發現和處理了Employee中Salary字段:
class Program
{
static void Main()
{
Employee liming = new Employee() { Name = "liming", Salary = 2000 };
BinarySerializer.SerializeToFile(liming, @"c:\", "person.txt");
Employee limingCopy = BinarySerializer.DeserializeFromFile<Employee>(@"c:\person.txt");
Console.WriteLine(string.Format("姓名:{0}", limingCopy.Name));
Console.WriteLine(string.Format("薪水:{0}", limingCopy.Salary));
}
}
public class Person
{
public string Name { get; set; }
}
[Serializable]
public class Employee : Person, ISerializable
{
public int Salary { get; set; }
public Employee()
{
}
protected Employee(SerializationInfo info, StreamingContext context)
{
Salary = info.GetInt32("Salary");
}
public override void GetObjectData(SerializationInfo info, StreamingContext context)
{
info.AddValue("Salary", Salary);
}
}
序列化工具類:

輸出為:
姓名:
薪水:2000
看見,Name字段並沒有正確處理。這需要我們修改類型Employee中受保護的構造方法GetObjectData方法,為它加入父類字段的處理:
[Serializable]
public class Employee : Person, ISerializable
{
public int Salary { get; set; }
public Employee()
{
}
protected Employee(SerializationInfo info, StreamingContext context)
{
Name = info.GetString("Name");
Salary = info.GetInt32("Salary");
}
public void GetObjectData(SerializationInfo info, StreamingContext context)
{
info.AddValue("Name", Name);
info.AddValue("Salary", Salary);
}
}
修改後輸出:
姓名:liming
薪水:2000
上面的例子中Person類未被設置成支持序列化。現在,假設Person類已經實現了ISerializable接口,那麼這個問題處理起來會相對容易,在子類Employee中,我們只需要調用父類受保護的構造方法和GetObjectData方法就可以了。如下所示:
[Serializable]
public class Person : ISerializable
{
public string Name { get; set; }
public Person()
{
}
protected Person(SerializationInfo info, StreamingContext context)
{
Name = info.GetString("Name");
}
public virtual void GetObjectData(SerializationInfo info, StreamingContext context)
{
info.AddValue("Name", Name);
}
}
[Serializable]
public class Employee : Person, ISerializable
{
public int Salary { get; set; }
public Employee()
{
}
protected Employee(SerializationInfo info, StreamingContext context)
: base(info, context)
{
Salary = info.GetInt32("Salary");
}
public override void GetObjectData(SerializationInfo info, StreamingContext context)
{
base.GetObjectData(info, context);
info.AddValue("Salary", Salary);
}
}
轉自:《編寫高質量代碼改善C#程序的157個建議》陸敏技