用一句Linq把一個集合的屬性值根據條件改了，其他值不變，linq屬性值

用一句Linq把一個集合的屬性值根據條件改了，其他值不變，linq屬性值

第一次發博。 - -

剛無聊看到群裡一位朋友在提問，大晚上沒人解答，遂自己默默打開了VS，敲起了代碼。

問題：請問怎麼將集合newFoods中Name含有"包子"的Number+1，LINQ可以一句話寫出來 ?

List<Food> newFoods = new List<Food>{
    new Food { Money = 10, Name = "天津包子", Number=1 },
    new Food { Money = 10, Name = "狗不理包子", Number = 1 },
    new Food { Money = 10, Name = "小籠包子", Number = 1 },
    new Food { Money = 10, Name = "饅頭", Number = 1 },
    new Food { Money = 10, Name = "粽子", Number = 1 }
};

我先是敲了一下正常的寫法，很快出來了。

但是用Linq一直不知道該怎麼寫，反而越寫越麻煩，還想出准備先篩選出一個對象，再把兩個對象合並的傻辦法。

後來發現原來select裡是可以直接查詢完返回原對象的。之前用Linq一直以為只能是 model.Select(o=>o.property==xxx) 這樣用，也沒去深究，看來是修為不夠。

1樓給出的代碼更加簡潔快速，Linq真是方便

最後的代碼：

 1         #region 
 2         public class Food
 3         {
 4             public string Name { get; set; }
 5             public int Money { get; set; }
 6             public int Number { get; set; }
 7         }
 8         static void Example1()
 9         {
10             List<Food> newFoods = new List<Food>{
11                new Food { Money = 10, Name = "天津包子", Number=1 },
12                new Food { Money = 10, Name = "狗不理包子", Number = 1 },
13                new Food { Money = 10, Name = "小籠包子", Number = 1 },
14                new Food { Money = 10, Name = "饅頭", Number = 1 },
15                new Food { Money = 10, Name = "粽子", Number = 1 }
16             };
17             //Linq寫法1
18             newFoods.ForEach(o =>
19             {
20                 o.Number = o.Name.Contains("包子") ? o.Number + 1 : o.Number;
21             });
22             //Linq寫法2
23             newFoods = newFoods.Select(o =>
24             {
25                 o.Number = o.Name.Contains("包子") ? o.Number + 1 : o.Number;
26                 return o;
27             }).ToList();
28             //普通寫法
29             for (int i = 0; i < newFoods.Count; i++)
30             {
31                 newFoods[i].Number = newFoods[i].Name.Contains("包子") ? newFoods[i].Number + 1 : newFoods[i].Number;
32             }
33             //遍歷輸出
34             foreach (Food food in newFoods)
35             {
36                 Console.WriteLine("名稱：" + food.Name + ",價格：" + food.Money + ",數量：" + food.Number);
37             }
38             Console.ReadLine();
39         }
40         #endregion