java-大神幫看下我的代碼哪裡錯了？

大神幫看下我的代碼哪裡錯了？

題目是編寫程序，讀入未指定個數的整數，判斷讀入的正數和負數分別有多少個，然後計算這些輸入值的總和及其平均值（不對0計數）。當輸入為0時，表明程序結束。將平均值以浮點數顯示。

import java.util.Scanner;
public class TextXXXXX {
public static void main (String[] args){
Scanner input = new Scanner(System.in);
int count1 = 0 , count2 = 0 , sum = 0 , num;
double avg;
System.out.print("請輸入一個整數，輸入0時結束:");
num = input.nextInt();
while(num != 0){
System.out.print("請輸入一個整數，輸入0時結束:");
num = input.nextInt();
while(num > 0)
count1+=1;
while(num < 0)
count2+=1;
sum+=num;
}
avg = sum /(count1 + count2);
System.out.println("整數個數為：" + count1 + " 負數個數為：" + count2);
System.out.println("和為：" + sum);
System.out.println("平均值為："+ avg);
}
}

最佳回答：

 public static void main(String[] args) {
        int count1 = 0, count2 = 0, sum = 0, num;
        double avg;
        for (int i = 1; i >0; i++) {
            Scanner input = new Scanner(System.in);
            System.out.print("請輸入一個整數，輸入0時結束:");
            num = input.nextInt();
            if (num > 0)
                count1 += 1;
            if (num < 0)
                count2 += 1;
            if(num==0){
                break;
            }
            sum += num;

        }
        avg = sum*1.0 / (count1 + count2);
        System.out.println("整數個數為：" + count1 + " 負數個數為：" + count2);
        System.out.println("和為：" + sum);
        System.out.println("平均值為：" + avg);

    }