strcmp-C語言 如何將 兩字符串的比較結果 作為 if 的判斷條件

C語言 如何將 兩字符串的比較結果 作為 if 的判斷條件

例如我有兩個字符串

 char i[9][13], j[13];

應該如何正確地將 i[2（或由前面的語句提供的一個數作）] ==(或!=) j 作為 if語句的判斷條件？(或!=)
我試過

 if(strcmp(i[n], j) !=0)   //string.h

和

 if(i[n]!=j)

上面兩個if代碼片段都嵌套與一個for代碼塊，n由for提供
程序都沒辦法正確執行這個if判斷，而是直接跳過了if代碼塊，執行下面的語句

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

FILE *input_file, *output_file;

int total_people, giving_to, accepting, having[9], money_counter;

char giver[9][13], receiver[9][13], the_giver[13], the_recever[13];

int people_scaner, people_judger;



int test_count;

int main () {
    input_file = fopen("gift1.in", "r");
    output_file = fopen("gift1.out", "w+");

    fscanf(input_file, "%d\n", &total_people);

    //read all name to a array called `giver[][]` and `receiver[][]`
    people_scaner = 0;

    while(people_scaner < total_people){
        fscanf(input_file, "%s", giver[people_scaner]);
        /*
         *&giver[people_scaner] = &receiver[people_judger];
         */
        people_scaner ++;
    }

    //read the first of who giving gift to others to `the_giver`
    fscanf(input_file, "%s", the_giver);

    //if the guy who is the first person on the list of `giver[]` eles increase the people_judger
    people_judger = 0;

    if(strcmp(the_giver, giver[people_judger]) != 0){
        people_judger ++;
    }


    //according to the number of last step, scan next two number to &having[people_judger] and giving_to, giving_to will be resuing 
    fscanf(input_file, "%d%d", &having[people_judger], &giving_to);
    accepting = having[people_judger] / giving_to;

    for(people_scaner = 0; people_scaner < giving_to; people_scaner++){
        //read a recever
        fscanf(input_file, "%s", the_recever);
        printf("%s\n", the_recever);
        //put the gift from the giver to the recever
        people_judger = 0;
        if(strcmp(the_giver, giver[people_judger]) != 0){       //這裡
            people_judger++;
            printf("%d\n", people_judger);
            continue;
        }
        having[people_judger] = accepting + having[people_judger];

        people_scaner++;
    }

    fclose(input_file);
    fclose(output_file);
    return 0;
}

所讀文件

5
dave
laura
owen
vick
arm
dave
200 3
laura
owen
vick
owen
500 1
dave
arm
150 2
vick
owen
laura
0 2
arm
vick
vick
0 0

題目來源
USACO Greedy Gift Givers

最佳回答：

int strcmp(char *str1,char *str2);
字符串比較函數
str1 str1=str2 返回0
str1>str2 返回正數

這是C語言的字符串，不能直接比較，C++的string類型，可以直接比較。