ios-打開SQlite數據庫的時候報錯

打開SQlite數據庫的時候報錯

用嵌入SQLite數據庫開發ios應用，我把數據庫放到SQlite管理員，然後拖到Xcode工程中。但是當我打開DB的時候，報錯 out of memory ，不知道是不是SQlite的bug，因為我的文件很小，應該不會報出內存問題。

初始化數據庫的代碼：

- (id)initWithPath:(NSString *)path {
if (self = [super init]) {
    BOOL success;
    NSError *error;
    NSFileManager *fileManager = [NSFileManager defaultManager];
    NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
    NSString *documentsDirectory = [paths objectAtIndex:0];
    NSString *dbPath = [documentsDirectory stringByAppendingPathComponent:@"SoundLib_DB.sqlite"];

    if ([fileManager fileExistsAtPath:dbPath] == NO) {
        NSString *resourcePath = [[NSBundle mainBundle] pathForResource:@"SoundLib_DB" ofType:@"sqlite"];
        [fileManager copyItemAtPath:resourcePath toPath:dbPath error:&error];
    }

    success = [fileManager fileExistsAtPath:dbPath];
    if(!success)
    {
        NSLog(@"Cannot locate database file '%@'.", dbPath);
    }
    sqlite3 *dbConnection;
//Here is when I get the error, at trying to open the DB
    if (sqlite3_open_v2("SoundLib", &dbConnection, SQLITE_OPEN_READWRITE, NULL) != SQLITE_OK) {
        NSLog(@"[SQLITE] Unable to open database!");
        NSLog(@"%s Prepare failure '%s' (%1d)", __FUNCTION__, sqlite3_errmsg(database), sqlite3_errcode(database));
        return nil;
    }
    database = dbConnection;
}
return self;
}

最佳回答：

報錯可能是由於數據庫路徑傳遞為UTF8String，我看見你傳遞"SoundLib"，不能這樣直接傳遞。

 if (sqlite3_open([dbPath UTF8String], &databaseHandle) == SQLITE_OK)
{
   //dbPath is your full database path you getting above
}

P.S.dbpath作為const char

const char *dbpath