android-Android進程條從0跳到100

Android進程條從0跳到100

AsyncTask代碼如下，文件更新什麼的都正常，就是想實現一個進度條時，直接從0跳到100了。

怎麼辦？

public class UploadingAsync extends AsyncTask<String, Integer, Object> {

  ProgressDialog dialog;
  BaseActivity base;

  public FileUploadAsyncTask(BaseActivity base) {
    this.base = base;
  }

  @Override
  protected Object doInBackground(String... path) {
    try {
      DroplrApp api = ((DroplrApplication) base.getApplication()).getDroplrAppApi();

      File file = new File(path[0]);

      Log.e("File uploaded", file.getAbsolutePath().toString());

      api.upload(file, new DroplrAppProgressListener() {

        @Override
        public void transferred(long transfer, long total) {
          publishProgress((int) (total * 100 / transfer));
        }
      });
    } catch (DroplrAppException e) {
      Log.e("Something is wrong", "Problem uploading");
    }

    return null;
  }

  @Override
  protected void onPreExecute() {
    super.onPreExecute();
    dialog = new ProgressDialog(base);
    dialog.setProgressStyle(ProgressDialog.STYLE_HORIZONTAL);
        dialog.setMessage("Uploading...");
        dialog.setIndeterminate(false);
        dialog.setCancelable(false);
        dialog.setMax(100);
        dialog.setProgress(0);
        dialog.show();
  }

  @Override
  protected void onPostExecute(Object result) {
    super.onPostExecute(result);
    dialog.dismiss();
  }

  @Override
  protected void onProgressUpdate(Integer... progress) {
    super.onProgressUpdate(progress);
    Log.e("progress", progress[0].toString());
    dialog.setProgress(progress[0]);
  }

}

Log.e("progress", progress[0].toString()); 的輸出：

前面都省略了。
06-08 15:24:13.223: E/progress(13418): 102
06-08 15:24:13.223: E/progress(13418): 102
06-08 15:24:13.223: E/progress(13418): 101
06-08 15:24:13.223: E/progress(13418): 101
06-08 15:24:13.223: E/progress(13418): 100
06-08 15:24:13.603: E/progress(13418): 100

06-08 15:24:13.648: E/progress(13418): 100

最佳回答：

這行：

publishProgress((int) (total * 100 / transfer));

應該是:

(int)(((float)transfer * 100f) / (float)total)