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 程式師世界 >> 編程語言 >> 更多編程語言 >> 更多關於編程 >> Python實現的簡單hangman游戲實例

Python實現的簡單hangman游戲實例

編輯:更多關於編程

       本文實例講述了Python實現的簡單hangman游戲。分享給大家供大家參考。具體如下:

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    1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 #!/usr/bin/env python import random import cPickle class Hangman(object): '''A simple hangman game that tries to improve your vocabulary a bit ''' def __init__(self): # the variables used, this is not necessary self.dumpfile = '' #the dictionary file self.dictionary = {} #the pickled dict self.words = [] #list of words used self.secret_word = '' #the 'key' self.length = 0 #length of the 'key' self.keys = [] #inputs that match the 'key' self.used_keys = [] #keys that are already used self.guess = '' #player's guess self.mistakes = 0 #number of incorrect inputs return self.load_dict() #insert some random hints for the player def insert_random(self, length): randint = random.randint # 3 hints if length >= 7: hint = 3 else: hint = 1 for x in xrange(hint): a = randint(1, length - 1) self.keys[a-1] = self.secret_word[a-1] def test_input(self): #if the guessed letter matches if self.guess in self.secret_word: indexes = [i for i, item in enumerate(self.secret_word) if item == self.guess] for index in indexes: self.keys[index] = self.guess self.used_keys.append(self.guess) print "used letters ",set(self.used_keys),'n' #if the guessed letter didn't match else: self.used_keys.append(self.guess) self.mistakes += 1 print "used letters ",set(self.used_keys),'n' # load the pickled word dictionary and unpickle them def load_dict(self): try : self.dumpfile = open("~/python/hangman/wordsdict.pkl", "r") except IOError: print "Couldn't find the file 'wordsdict.pkl'" quit() self.dictionary = cPickle.load(self.dumpfile) self.words = self.dictionary.keys() self.dumpfile.close() return self.prepare_word() #randomly choose a word for the challenge def prepare_word(self): self.secret_word = random.choice(self.words) #don't count trailing spaces self.length = len(self.secret_word.rstrip()) self.keys = ['_' for x in xrange(self.length)] self.insert_random(self.length) return self.ask() #display the challenge def ask(self): print ' '.join(self.keys), ":", self.dictionary[self.secret_word] print return self.input_loop() #take input from the player def input_loop(self): #four self.mistakes are allowed chances = len(set(self.secret_word)) + 4 while chances != 0 and self.mistakes < 5: try: self.guess = raw_input("> ") except EOFError: exit(1) self.test_input() print ' '.join(self.keys) if '_' not in self.keys: print 'well done!' break chances -= 1 if self.mistakes > 4: print 'the word was', ''.join(self.secret_word).upper() return self.quit_message() def quit_message(self): print "n" print "Press 'c' to continue, or any other key to quit the game. " print "You can always quit the game by pressing 'Ctrl+D'" try: command = raw_input('> ') if command == 'c': return self.__init__() #loopback else : exit(0) except EOFError: exit(1) if __name__ == '__main__': game = Hangman() game.__init__()

      希望本文所述對大家的Python程序設計有所幫助。

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