程序師世界是廣大編程愛好者互助、分享、學習的平台,程序師世界有你更精彩!
首頁
編程語言
C語言|JAVA編程
Python編程
網頁編程
ASP編程|PHP編程
JSP編程
數據庫知識
MYSQL數據庫|SqlServer數據庫
Oracle數據庫|DB2數據庫
您现在的位置: 程式師世界 >> 編程語言 >  >> 更多編程語言 >> Python

Python zip and unzip data

編輯:Python
# zipping and unzipping a string using the zlib module
a very large string could be zipped and saved to a file speeding up file writing time
and later reloaded and unzipped by another program speeding up reading of the file
tested with Python24 vegaseat 15aug2005
import zlib
str1 = \
"""Dallas Cowboys football practice at Valley Ranch was delayed on Wednesday
for nearly two hours. One of the players, while on his way to the locker
room happened to look down and notice a suspicious looking, unknown white
powdery substance on the practice field.
The coaching staff immediately suspended practice while the FBI was
called in to investigate. After a complete field analysis, the FBI
determined that the white substance unknown to the players was the goal
line.
Practice was resumed when FBI Special Agents decided that the team would not
be likely to encounter the substance again.
"""
print '-'70 # 70 dashes for the fun of it
print str1
print '-'70
crc_check1 = zlib.crc32(str1)
print "crc before zip=", crc_check1
print "Length of original str1 =", len(str1)
zip compress the string
zstr1 = zlib.compress(str1)
print "Length of zipped str1 =", len(zstr1)
filename = 'Dallas.zap'
write the zipped string to a file
fout = open(filename, 'w')
try:
print >> fout, zstr1
except IOError:
print "Failed to open file..."
else:
print "done writing", filename
fout.close()
read the zip file back
fin = open(filename, 'r')
try:
zstr2 = fin.read()
except IOError:
print "Failed to open file..."
else:
print "done reading", filename
fin.close()
unzip the zipped string from the file
str2 = zlib.decompress(zstr2)
print '-'70
print str2
print '-'70
crc_check2 = zlib.crc32(str2)
print "crc after unzip =", crc_check2, "(check sums should match)"</pre> 

  1. 上一篇文章:
  2. 下一篇文章:
Copyright © 程式師世界 All Rights Reserved