java數據構造與算法當中綴表達式轉為後綴表達式的辦法

java數據構造與算法當中綴表達式轉為後綴表達式的辦法。本站提示廣大學習愛好者：（java數據構造與算法當中綴表達式轉為後綴表達式的辦法）文章只能為提供參考，不一定能成為您想要的結果。以下是java數據構造與算法當中綴表達式轉為後綴表達式的辦法正文

本文實例講述了java數據構造與算法當中綴表達式轉為後綴表達式的辦法。分享給年夜家供年夜家參考，詳細以下：

//stack
public class StackX {
  private int top;
  private char[] stackArray;
  private int maxSize;
  //constructor
  public StackX(int maxSize){
    this.maxSize = maxSize;
    this.top = -1;
    stackArray = new char[this.maxSize];
  }
  //put item on top of stack
  public void push(char push){
    stackArray[++top] = push;
  }
  //take item from top of stack
  public char pop(){
    return stackArray[top--];
  }
  //peek the top item from stack
  public char peek(){
    return stackArray[top];
  }
  //peek the character at index n
  public char peekN(int index){
    return stackArray[index];
  }
  //true if stack is empty
  public boolean isEmpty(){
    return (top == -1);
  }
  //return stack size
  public int size(){
    return top+1;
  }
}
//InToPost
public class InToPost {
  private StackX myStack;
  private String input;
  private String outPut="";
  //constructor
  public InToPost(String input){
    this.input = input;
    myStack = new StackX(this.input.length());
  }
  //do translation to postFix
  public String doTrans(){
    for(int i=0; i<input.length(); i++){
      char ch = input.charAt(i);
      switch(ch){
      case '+':
      case '-':
        this.getOper(ch,1);
        break;
      case '*':
      case '/':
        this.getOper(ch,2);
        break;
      case '(':
        this.getOper(ch, 3);
        break;
      case ')':
        this.getOper(ch, 4);
        break;
      default:
        this.outPut = this.outPut + ch;
      }
    }
    while(!this.myStack.isEmpty()){
      this.outPut = this.outPut + this.myStack.pop();
    }
    return this.outPut;
  }
  //get operator from input
  public void getOper(char ch, int prect1){
    char temp;
    if(this.myStack.isEmpty()||prect1==3){
      this.myStack.push(ch);
    }
    else if(prect1==4){
      while(!this.myStack.isEmpty()){
        temp = this.myStack.pop();
        if(temp=='(')continue;
        this.outPut = this.outPut + temp;
      }
    }
    else if(prect1==1){
      temp = this.myStack.peek();
      if(temp=='(') this.myStack.push(ch);
      else{
        this.outPut = this.outPut + this.myStack.pop();
        this.myStack.push(ch);
      }
    }
    else{
      temp = this.myStack.peek();
      if(temp=='('||temp=='+'||temp=='-') this.myStack.push(ch);
      else{
        this.outPut = this.outPut + this.myStack.pop();
      }
    }
  }
}
//Test
public class TestInToPost {
  private static InToPost inToPost;
  private static String str;
  public static void main(String []args){
    str = "((A+B)*C)-D";
    inToPost = new InToPost(str);
    System.out.println(inToPost.doTrans());
  }
}

PS:算法完成不是很完美，有些龐雜的表達式解析要失足，寫出來做個留念！

願望本文所述對年夜家java法式設計有所贊助。