程序師世界是廣大編程愛好者互助、分享、學習的平台,程序師世界有你更精彩!
首頁
編程語言
C語言|JAVA編程
Python編程
網頁編程
ASP編程|PHP編程
JSP編程
數據庫知識
MYSQL數據庫|SqlServer數據庫
Oracle數據庫|DB2數據庫
 程式師世界 >> 數據庫知識 >> 其他數據庫知識 >> 更多數據庫知識 >> 查詢數據排名情況SQL

查詢數據排名情況SQL

編輯:更多數據庫知識

1/准備測試數據

---------------------------------------------------------------------------------
create table t1(
c1 integer,
c2 integer,
c3 integer
);

insert into t1 values(1,2,3)

insert into t1 values(1,8,4)
insert into t1 values(1,4,4)

insert into t1 values(1,4,5)

insert into t1 values(1,5,5)

insert into t1 values(2,2,3)

insert into t1 values(2,8,4)
insert into t1 values(2,4,4)

insert into t1 values(2,4,5)

insert into t1 values(2,5,5)

2/查看排名

---------------------------------------------------------------------------------

A/單記錄排名

select c1,c3,
(select count( c3)+1 from t1 a where a.c3>b.c3
and a.c1=b.c1 and a.c1 =1
) order_num
from t1 b
where  c1 =1
order by c1,c3

c1          c3          order_num             
----------- ----------- ----------------------
1           3           5                     
1           4           3                     
1           4           3                     
1           5           1                     
1           5           1     
B/多記錄排名

select c1,c2,c3,
(select count( c3)+1 from t1 a where a.c3>b.c3
and a.c1=b.c1
) order_num
from t1 b
order by c1,c3


c1          c2          c3          order_num             
----------- ----------- ----------- ----------------------
1           2           3           5                     
1           8           4           3                     
1           4           4           3                     
1           4           5           1                     
1           5           5           1                     
2           2           3           5                     
2           8           4           3                     
2           4           4           3                     
2           4           5           1                     
2           5           5           1  

 

  1. 上一頁:
  2. 下一頁:
Copyright © 程式師世界 All Rights Reserved