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 程式師世界 >> 數據庫知識 >> 其他數據庫知識 >> MSSQL >> 50個經常使用sql語句 網下流行的先生選課表的例子

50個經常使用sql語句 網下流行的先生選課表的例子

編輯:MSSQL

50個經常使用sql語句 網下流行的先生選課表的例子。本站提示廣大學習愛好者:(50個經常使用sql語句 網下流行的先生選課表的例子)文章只能為提供參考,不一定能成為您想要的結果。以下是50個經常使用sql語句 網下流行的先生選課表的例子正文


50個經常使用sql語句

Student(S#,Sname,Sage,Ssex) 先生表
Course(C#,Cname,T#) 課程表
SC(S#,C#,score) 成就表
Teacher(T#,Tname) 教員表

成績:
1、查詢“001”課程比“002”課程成就高的一切先生的學號;
select a.S# from (select s#,score from SC where C#='001') a,(select s#,score
from SC where C#='002') b
where a.score>b.score and a.s#=b.s#;
2、查詢均勻成就年夜於60分的同窗的學號戰爭均成就;
select S#,avg(score)
from sc
group by S# having avg(score) >60;
3、查詢一切同窗的學號、姓名、選課數、總成就;
select Student.S#,Student.Sname,count(SC.C#),sum(score)
from Student left Outer join SC on Student.S#=SC.S#
group by Student.S#,Sname
4、查詢姓“李”的先生的個數;
select count(distinct(Tname))
from Teacher
where Tname like '李%';
5、查詢沒學過“葉平”先生課的同窗的學號、姓名;
select Student.S#,Student.Sname
from Student
where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平');
6、查詢學過“001”而且也學過編號“002”課程的同窗的學號、姓名;
select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');
7、查詢學過“葉平”先生所教的一切課的同窗的學號、姓名;
select S#,Sname
from Student
where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname='葉平'));
8、查詢課程編號“002”的成就比課程編號“001”課程低的一切同窗的學號、姓名;
Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2
from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2 <score;
9、查詢一切課程成就小於60分的同窗的學號、姓名;
select S#,Sname
from Student
where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60);
10、查詢沒有學全一切課的同窗的學號、姓名;
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);
11、查詢至多有一門課與學號為“1001”的同窗所學雷同的同窗的學號和姓名;
select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='1001';
12、查詢至多學過學號為“001”同窗一切一門課的其他同窗學號和姓名;
select distinct SC.S#,Sname
from Student,SC
where Student.S#=SC.S# and C# in (select C# from SC where S#='001');
13、把“SC”表中“葉平”先生教的課的成就都更改成此課程的均勻成就;
update SC set score=(select avg(SC_2.score)
from SC SC_2
where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='葉平');
14、查詢和“1002”號的同窗進修的課程完整雷同的其他同窗學號和姓名;
select S# from SC where C# in (select C# from SC where S#='1002')
group by S# having count(*)=(select count(*) from SC where S#='1002');
15、刪除進修“葉平”先生課的SC表記載;
Delect SC
from course ,Teacher
where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='葉平';
16、向SC表中拔出一些記載,這些記載請求相符以下前提:沒有上過編號“003”課程的同窗學號、2、
號課的均勻成就;
Insert SC select S#,'002',(Select avg(score)
from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002');
17、按均勻成就從高到低顯示一切先生的“數據庫”、“企業治理”、“英語”三門的課程成就,按以下情勢顯示: 先生ID,,數據庫,企業治理,英語,有用課程數,有用均勻分
SELECT S# as 先生ID
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS 數據庫
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企業治理
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英語
,COUNT(*) AS 有用課程數, AVG(t.score) AS 均勻成就
FROM SC AS t
GROUP BY S#
ORDER BY avg(t.score)
18、查詢各科成就最高和最低的分:以以下情勢顯示:課程ID,最高分,最低分
SELECT L.C# As 課程ID,L.score AS 最高分,R.score AS 最低分
FROM SC L ,SC AS R
WHERE L.C# = R.C# and
L.score = (SELECT MAX(IL.score)
FROM SC AS IL,Student AS IM
WHERE L.C# = IL.C# and IM.S#=IL.S#
GROUP BY IL.C#)
AND
R.Score = (SELECT MIN(IR.score)
FROM SC AS IR
WHERE R.C# = IR.C#
GROUP BY IR.C#
);
19、按各科均勻成就從低到高和合格率的百分數從高到低次序
SELECT t.C# AS 課程號,max(course.Cname)AS 課程名,isnull(AVG(score),0) AS 均勻成就
,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 合格百分數
FROM SC T,Course
where t.C#=course.C#
GROUP BY t.C#
ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
20、查詢以下課程均勻成就和合格率的百分數(用"1行"顯示): 企業治理(001),馬克思(002),OO&UML (003),數據庫(004)
SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企業治理均勻分
,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企業治理合格百分數
,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 馬克思均勻分
,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 馬克思合格百分數
,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML均勻分
,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML合格百分數
,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 數據庫均勻分
,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 數據庫合格百分數
FROM SC
21、查詢分歧先生所教分歧課程均勻分從高到低顯示
SELECT max(Z.T#) AS 教員ID,MAX(Z.Tname) AS 教員姓名,C.C# AS 課程ID,MAX(C.Cname) AS 課程稱號,AVG(Score) AS 均勻成就
FROM SC AS T,Course AS C ,Teacher AS Z
where T.C#=C.C# and C.T#=Z.T#
GROUP BY C.C#
ORDER BY AVG(Score) DESC
22、查詢以下課程成就第 3 名到第 6 名的先生成就單:企業治理(001),馬克思(002),UML (003),數據庫(004)
[先生ID],[先生姓名],企業治理,馬克思,UML,數據庫,均勻成就
SELECT DISTINCT top 3
SC.S# As 先生學號,
Student.Sname AS 先生姓名 ,
T1.score AS 企業治理,
T2.score AS 馬克思,
T3.score AS UML,
T4.score AS 數據庫,
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 總分
FROM Student,SC LEFT JOIN SC AS T1
ON SC.S# = T1.S# AND T1.C# = '001'
LEFT JOIN SC AS T2
ON SC.S# = T2.S# AND T2.C# = '002'
LEFT JOIN SC AS T3
ON SC.S# = T3.S# AND T3.C# = '003'
LEFT JOIN SC AS T4
ON SC.S# = T4.S# AND T4.C# = '004'
WHERE student.S#=SC.S# and
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
NOT IN
(SELECT
DISTINCT
TOP 15 WITH TIES
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
FROM sc
LEFT JOIN sc AS T1
ON sc.S# = T1.S# AND T1.C# = 'k1'
LEFT JOIN sc AS T2
ON sc.S# = T2.S# AND T2.C# = 'k2'
LEFT JOIN sc AS T3
ON sc.S# = T3.S# AND T3.C# = 'k3'
LEFT JOIN sc AS T4
ON sc.S# = T4.S# AND T4.C# = 'k4'
ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);

23、統計列印各科成就,各分數段人數:課程ID,課程稱號,[100-85],[85-70],[70-60],[ <60]
SELECT SC.C# as 課程ID, Cname as 課程稱號
,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]
,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70]
,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60]
,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
FROM SC,Course
where SC.C#=Course.C#
GROUP BY SC.C#,Cname;

24、查詢先生均勻成就及其名次
SELECT 1+(SELECT COUNT( distinct 均勻成就)
FROM (SELECT S#,AVG(score) AS 均勻成就
FROM SC
GROUP BY S#
) AS T1
WHERE 均勻成就 > T2.均勻成就) as 名次,
S# as 先生學號,均勻成就
FROM (SELECT S#,AVG(score) 均勻成就
FROM SC
GROUP BY S#
) AS T2
ORDER BY 均勻成就 desc;

25、查詢各科成就前三名的記載:(不斟酌成就並列情形)
SELECT t1.S# as 先生ID,t1.C# as 課程ID,Score as 分數
FROM SC t1
WHERE score IN (SELECT TOP 3 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
26、查詢每門課程被選修的先生數
select c#,count(S#) from sc group by C#;
27、查詢出只選修了一門課程的全體先生的學號和姓名
select SC.S#,Student.Sname,count(C#) AS 選課數
from SC ,Student
where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1;
28、查詢男生、女生人數
Select count(Ssex) as 男生人數 from Student group by Ssex having Ssex='男';
Select count(Ssex) as 女生人數 from Student group by Ssex having Ssex='女';
29、查詢姓“張”的先生名單
SELECT Sname FROM Student WHERE Sname like '張%';
30、查詢同名異性先生名單,並統計同名人數
select Sname,count(*) from Student group by Sname having count(*)>1;;
31、1981年出身的先生名單(注:Student表中Sage列的類型是datetime)
select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age
from student
where CONVERT(char(11),DATEPART(year,Sage))='1981';
32、查詢每門課程的均勻成就,成果按均勻成就升序分列,均勻成就雷同時,按課程號降序分列
Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ;
33、查詢均勻成就年夜於85的一切先生的學號、姓名戰爭均成就
select Sname,SC.S# ,avg(score)
from Student,SC
where Student.S#=SC.S# group by SC.S#,Sname having avg(score)>85;
34、查詢課程稱號為“數據庫”,且分數低於60的先生姓名和分數
Select Sname,isnull(score,0)
from Student,SC,Course
where SC.S#=Student.S# and SC.C#=Course.C# and Course.Cname='數據庫'and score <60;
35、查詢一切先生的選課情形;
SELECT SC.S#,SC.C#,Sname,Cname
FROM SC,Student,Course
where SC.S#=Student.S# and SC.C#=Course.C# ;
36、查詢任何一門課程成就在70分以上的姓名、課程稱號和分數;
SELECT distinct student.S#,student.Sname,SC.C#,SC.score
FROM student,Sc
WHERE SC.score>=70 AND SC.S#=student.S#;
37、查詢不合格的課程,並按課程號從年夜到小分列
select c# from sc where scor e <60 order by C# ;
38、查詢課程編號為003且課程成就在80分以上的先生的學號和姓名;
select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score>80 and C#='003';
39、求選了課程的先生人數
select count(*) from sc;
40、查詢選修“葉平”先生所講課程的先生中,成就最高的先生姓名及其成就
select Student.Sname,score
from Student,SC,Course C,Teacher
where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname='葉平' and SC.score=(select max(score)from SC where C#=C.C# );
41、查詢各個課程及響應的選修人數
select count(*) from sc group by C#;
42、查詢分歧課程成就雷同的先生的學號、課程號、先生成就
select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ;
43、查詢每門功成就最好的前兩名
SELECT t1.S# as 先生ID,t1.C# as 課程ID,Score as 分數
FROM SC t1
WHERE score IN (SELECT TOP 2 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
44、統計每門課程的先生選修人數(跨越10人的課程才統計)。請求輸入課程號和選修人數,查詢成果按人數降序分列,查詢成果按人數降序分列,若人數雷同,按課程號升序分列
select C# as 課程號,count(*) as 人數
from sc
group by C#
order by count(*) desc,c#
45、檢索至多選修兩門課程的先生學號
select S#
from sc
group by s#
having count(*) > = 2
46、查詢全體先生都選修的課程的課程號和課程名
select C#,Cname
from Course
where C# in (select c# from sc group by c#)
47、查詢沒學過“葉平”先生講解的任一門課程的先生姓名
select Sname from Student where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='葉平');
48、查詢兩門以上不合格課程的同窗的學號及其均勻成就
select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score <60 group by S# having count(*)>2)group by S#;
49、檢索“004”課程分數小於60,按分數降序分列的同窗學號
select S# from SC where C#='004'and score <60 order by score desc;
50、刪除“002”同窗的“001”課程的成就
delete from Sc where S#='001'and C#='001';

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