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 程式師世界 >> 數據庫知識 >> SqlServer數據庫 >> 關於SqlServer >> SQLServer加密存儲過程的破解問題

SQLServer加密存儲過程的破解問題

編輯:關於SqlServer
CREATE PROCEDURE sp_decrypt(@objectName varchar(50))
  AS
  begin
  set nocount on
  --CSDN:j9988 copyright:2004.04.15
  --V3.1
  --破解字節不受限制,適用於SQLSERVER2000存儲過程,函數,視圖,觸發器
  --修正上一版視圖觸發器不能正確解密錯誤
  --發現有錯,請E_MAIL:[email protected]
  begin tran
  declare @objectname1 varchar(100),@orgvarbin varbinary(8000)
  declare @sql1 nvarchar(4000),@sql2 varchar(8000),@sql3 nvarchar(4000),@sql4 nvarchar(4000)
  DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)
  declare @i int,@status int,@type varchar(10),@parentid int
  declare @colid int,@n int,@q int,@j int,@k int,@encrypted int,@number int
  select @type=xtype,@parentid=parent_obj from sysobjects where id=object_id(@ObjectName)
  
  create table #temp(number int,colid int,ctext varbinary(8000),encrypted int,status int)
  insert #temp SELECT number,colid,ctext,encrypted,status FROM syscomments WHERE id = object_id(@objectName)
  select @number=max(number) from #temp
  set @k=0
  
  while @k<=@number
  begin
  if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)
  begin
  if @type='P'
  set @sql1=(case when @number>1 then 'ALTER PROCEDURE '+ @objectName +';'+rtrim(@k)+' WITH ENCRYPTION AS '
  else 'ALTER PROCEDURE '+ @objectName+' WITH ENCRYPTION AS '
  end)
  
  if @type='TR'
  begin
  declare @parent_obj varchar(255),@tr_parent_xtype varchar(10)
  select @parent_obj=parent_obj from sysobjects where id=object_id(@objectName)
  select @tr_parent_xtype=xtype from sysobjects where id=@parent_obj
  if @tr_parent_xtype='V'
  begin
  set @sql1='ALTER TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION INSTERD OF INSERT AS PRINT 1 '
  end
  else
  begin
  set @sql1='ALTER TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR INSERT AS PRINT 1 '
  end
  
  end
  if @type='FN' or @type='TF' or @type='IF'
  set @sql1=(case @type when 'TF' then
  'ALTER FUNCTION '+ @objectName+'(@a char(1)) returns @b table(a

 

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