PHP日期函數date格式化UNIX時間的方法

本文實例講述了PHP日期函數date格式化UNIX時間的方法。分享給大家供大家參考。具體分析如下：

日期函數可以根據指定的格式將一個unix時間格式化成想要的文本輸出

使用到函數語法如下

string date (string $Format);
string date (string $Format, int $Time);

下面是演示代碼

<?php
echo "When this page was loaded,\n";
echo 'It was then ', date ('r'), "\n";
echo 'The currend date was ', date ('F j, Y'), "\n";
echo 'The currend date was ', date ('M j, Y'), "\n";
echo 'The currend date was ', date ('m/d/y'), "\n";
echo 'The currend date was the ', date ('jS \o\f M, Y'), "\n";
echo 'The currend time was ', date ('g:i:s A T'), "\n";
echo 'The currend time was ', date ('H:i:s O'), "\n";
echo date ('Y');
date ('L')?(print ' is'):(print ' is not');
echo " a leap year\n";
echo time ('U'), " seconds had elapsed since January 1, 1970.\n";
?>

輸出結果如下

It was then Sat, 26 Dec 2009 07:09:51 +0000
The currend date was December 26, 2009
The currend date was Dec 26, 2009
The currend date was 12/26/09
The currend date was the 26th of Dec, 2009
The currend time was 7:09:51 AM GMT
The currend time was 07:09:51 +0000
2009 is not a leap year
1261811391 seconds had elapsed since January 1, 1970.

希望本文所述對大家的php程序設計有所幫助。