Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution.
Example:
Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2 + 7 = 9, return [0, 1].
UPDATE (2016/2/13):
The return format had been changed to zero-based indices. Please read the above updated description carefully.
1 class Solution {
2 public:
3 vector<int> twoSum(vector<int>& nums, int target) {
4 vector<int> ret(2,-1);
5
6 unordered_map<int,int> myMap;
7
8 for(int i = 0 ; i < nums.size(); i++){
9 if(myMap.find(target-nums[i]) == myMap.end()){
10 myMap[nums[i]] = i;
11 }else{
12 ret[0] = myMap[target-nums[i]];
13 ret[1] = i;
14 return ret;
15 }
16 }
17 return ret;
18 }
19 };