You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
處理好進位
1 /**
2 * Definition for singly-linked list.
3 * struct ListNode {
4 * int val;
5 * ListNode *next;
6 * ListNode(int x) : val(x), next(NULL) {}
7 * };
8 */
9 class Solution {
10 public:
11 ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
12 ListNode* newHead = new ListNode(0);
13 ListNode* pNode = newHead;
14
15 int num = 0;
16
17 while(l1 != NULL || l2 != NULL){
18 int val = num + (l1 ? l1->val : 0) + (l2 ? l2->val: 0);
19 num = val /10;
20 val = val % 10;
21 pNode->next = new ListNode(val);
22 pNode = pNode->next;
23 if(l1 != NULL){
24 l1 = l1->next;
25 }
26 if(l2 != NULL){
27 l2 = l2->next;
28 }
29 }
30 if(num != 0){
31 pNode->next = new ListNode(num);
32 pNode = pNode->next;
33 }
34 return newHead->next;
35 }
36 };