思路:這題和堆排序有類似,查找過程中從右上方的數字開始,如果該數字比查找的數字小,那麼該數字所在行可以刪除,不用繼續考慮;如果該數字比查找的數字大,那麼該數字所在列可以刪除。這樣,每次執行,都會刪除一行或者一列,極端情況下,執行2n次。
1 #include "stdafx.h"
2 #include<stdio.h>
3
4 bool Find(int* matrix, int rows, int columns, int number)
5 {
6 bool found = false;
7
8 if(matrix != NULL && rows > 0 && columns > 0)
9 {
10 int row = 0;
11 int column = columns - 1;
12 while(row < rows && column >= 0)
13 {
14 if(matrix[row*columns + column] == number)
15 {
16 found = true;
17 printf("the number %d is in row: %d and column: %d\n", number, row+1, column +1);
18 break;
19 }
20 else if(matrix[row*columns + column] > number)
21 -- column;
22 else
23 ++ row;
24 }
25 }
26
27 return found;
28 }
29
30 void Test(char* testName, int* matrix, int rows, int columns, int number, bool expected)
31 {
32 if(testName != NULL)
33 printf("%s begins.\n", testName);
34
35 bool result = Find(matrix, rows, columns, number);
36 if(result == expected)
37 printf("Passed.\n");
38 else
39 printf("Failed.\n");
40 }
41
42 void Test1()
43 {
44 int matrix[][4] = {{1,2,8,9}, {2,4,9,12},{4,7,10,13},{6,8,11,15}};
45 Test("Test1", (int*)matrix, 4,4,7,true);
46 }
47
48 // 1 2 8 9
49 // 2 4 9 12
50 // 4 7 10 13
51 // 6 8 11 15
52 int main()
53 {
54 int rows = 4;
55 int columns = 4;
56 int number = 7;
57 int matrix[][4] = {{1,2,8,9}, {2,4,9,12},{4,7,10,13},{6,8,11,15}};
58
59 for(int i = 0 ; i < rows; i++)
60 {
61 for(int j = 0 ;j < columns; j++)
62 printf("%d\t", matrix[i][j]);
63
64 printf("\n");
65 }
66 printf("\n");
67 bool result = Find((int*)matrix, rows, columns, number);
68 if(result)
69 printf("found.\n");
70 else
71 printf("not found.\n");
72
73 return 0;
74 }
