Given a binary tree, return all root-to-leaf paths.
For example, given the following binary tree:
1 / \ 2 3 \ 5
All root-to-leaf paths are:
["1->2->5", "1->3"]
Credits:
Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.
//簡單的二叉樹遍歷,遍歷的過程中記錄之前的路徑,一旦遍歷到葉子節點便將該路徑加入結果中。
class Solution {
public:
vector binaryTreePaths(TreeNode* root) {
vector res;
if (root==NULL) return res;
binaryTreePaths(res, root, to_string(root->val));
return res;
}
void binaryTreePaths(vector& result, TreeNode* node, string s) {
if (node->left==NULL && node->right==NULL)
{
result.push_back(s);
return;
}
if (node->left) binaryTreePaths(result, node->left, s + "->" + to_string(node->left->val));
if (node->right) binaryTreePaths(result, node->right, s + "->" + to_string(node->right->val));
}
};
