Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead.
For example, given the array [2,3,1,2,4,3] and s = 7,
the subarray [4,3] has the minimal length under the problem constraint.
[思路]
兩個指針, start end, end向後走,直到 sum 大於 s. 然後start向後, 直到sum 小於s. 同時更新 min值.
public class Solution {
//1,1,4
public int minSubArrayLen(int s, int[] nums) {
//init check
int start = 0;
int end = 0;
int sum = 0;
int min = Integer.MAX_VALUE;
while(start=s && start<=end) {
min = Math.min(min, end-start);
sum -= nums[start++];
}
}
return min==Integer.MAX_VALUE ? 0 : min;
}
}