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 程式師世界 >> 編程語言 >> C語言 >> C++ >> C++入門知識 >> UVA - 11384 - Help is needed for Dexter (找規律!!)

UVA - 11384 - Help is needed for Dexter (找規律!!)

編輯:C++入門知識

UVA - 11384 - Help is needed for Dexter (找規律!!)


UVA - 11384

Help is needed for Dexter Time Limit: 3000MS Memory Limit: Unknown 64bit IO Format: %lld & %llu

 

Submit Status

Description


Problem H

Help is needed for Dexter

Time Limit: 3 Second

 

Dexter is tired of Dee Dee. So he decided to keep Dee Dee busy in a game. The game he planned for her is quite easy to play but not easy to win at least not for Dee Dee. But Dexter does not have time to spend on this silly task, so he wants your help.

 

There will be a button, when it will be pushed a random number N will be chosen by computer. Then on screen there will be numbers from 1 to N. Dee Dee can choose any number of numbers from the numbers on the screen, and then she will command computer to subtract a positive number chosen by her (not necessarily on screen) from the selected numbers. Her objective will be to make all the numbers 0.

 

For example if N = 3, then on screen there will be 3 numbers on screen: 1, 2, 3. Say she now selects 1 and 2. Commands to subtract 1, then the numbers on the screen will be: 0, 1, 3. Then she selects 1 and 3 and commands to subtract 1. Now the numbers are 0, 0, 2. Now she subtracts 2 from 2 and all the numbers become 0.

 

Dexter is not so dumb to understand that this can be done very easily, so to make a twist he will give a limit L for each N and surely L will be as minimum as possible so that it is still possible to win within L moves. But Dexter does not have time to think how to determine L for each N, so he asks you to write a code which will take N as input and give L as output.

 

Input and Output:

Input consists of several lines each with N such that 1 ≤ N ≤ 1,000,000,000. Input will be terminated by end of file. For each N output L in separate lines.

 

SAMPLE INPUT

OUTPUT FOR SAMPLE INPUT

1

2

3

1

2

2

 

Problemsetter: Md. Mahbubul Hasan

Source

Root :: Prominent Problemsetters :: Md. Mahbubul Hasan
Root :: AOAPC I: Beginning Algorithm Contests -- Training Guide (Rujia Liu) :: Chapter 1. Algorithm Design :: General Problem Solving Techniques :: Examples
Root :: Competitive Programming 3: The New Lower Bound of Programming Contests (Steven & Felix Halim) :: Mathematics :: Ad Hoc Mathematics Problems :: Logarithm, Exponentiation, Power

 

 

 

期末之前再水個題,,近期可能會因為復習暫停AC之旅啦

 

思路:找規律,f [ n ] = f [ n / 2 ] + 1;

 

AC代碼:

#include 
#include 
#include 
using namespace std;

int fun(int n)
{
	return n == 1 ? 1 : fun(n/2) + 1;
}

int main()
{
	int n;
	while(scanf(%d, &n) == 1)
	{
		printf(%d
, fun(n));
	}
	return 0;
} 


 

 

 

 

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