There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).
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題意:求兩個有序數組的組成一個新的數組的中位數
思路:題目轉換為求第k大的數,如果總個數是奇數的話,就是求第中間的數了,如果是偶數的話,就是找到兩個中間的,求平均數。
求第k大的數:首先假設我們求的是兩個數組A和B中第k個數,為了我們每次都能折半查找,我們比較A[k/2]和B[k/2]這兩個數,如果A[k/2-1]
class Solution {
public:
double findMedianSortedArrays(int A[], int m, int B[], int n) {
int size = m + n;
int k = (m + n + 1) / 2;
if (size & 1)
return findKth(A, m, B, n, k);
else return (findKth(A, m, B, n, k) + findKth(A, m, B, n, k+1)) / 2;
}
double findKth(int A[], int m, int B[], int n, int k) {
if (m > n)
return findKth(B, n, A, m, k);
if (m == 0)
return B[k - 1];
if (k == 1)
return A[0] < B[0] ? A[0] : B[0];
int index = k / 2;
int left = index < m ? index : m;
int right = k - left;
if (A[left - 1] < B[right - 1])
return findKth(A + left, m - left, B, n, right);
else if (A[left - 1] > B[right - 1])
return findKth(A, m, B + right, n - right, left);
else return A[left - 1];
}
};