There are N gas stations along a circular route, where the amount of gas at station i is gas[i].
You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.
Return the starting gas station's index if you can travel around the circuit once, otherwise return -1.
Note:
The solution is guaranteed to be unique.
貪心法 如果此前一段的和小於零,則從以下一個加油站為起點,最後判斷加的氣是否大於用掉的氣,思路參照leetcodee題解
public class Solution {
public int canCompleteCircuit(int[] gas, int[] cost) {
int all = 0;
int sum = 0;
int res = -1;
for(int i = 0;i=0){
sum +=gas[i]-cost[i];
}else{
sum = 0;
res =i;
}
}
return all>=0?(res+1):-1;
}
}