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 程式師世界 >> 編程語言 >> C語言 >> C++ >> C++入門知識 >> poj 3009 Curling 2.0 (dfs )

poj 3009 Curling 2.0 (dfs )

編輯:C++入門知識

poj 3009 Curling 2.0 (dfs )


Curling 2.0 Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 11879 Accepted: 5028

Description

On Planet MM-21, after their Olympic games this year, curling is getting popular. But the rules are somewhat different from ours. The game is played on an ice game board on which a square mesh is marked. They use only a single stone. The purpose of the game is to lead the stone from the start to the goal with the minimum number of moves.

Fig. 1 shows an example of a game board. Some squares may be occupied with blocks. There are two special squares namely the start and the goal, which are not occupied with blocks. (These two squares are distinct.) Once the stone begins to move, it will proceed until it hits a block. In order to bring the stone to the goal, you may have to stop the stone by hitting it against a block, and throw again.

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Fig. 1: Example of board (S: start, G: goal)<喎?http://www.Bkjia.com/kf/ware/vc/" target="_blank" class="keylink">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"center">\
Fig. 2: Stone movements

Under the rules, we would like to know whether the stone at the start can reach the goal and, if yes, the minimum number of moves required.

With the initial configuration shown in Fig. 1, 4 moves are required to bring the stone from the start to the goal. The route is shown in Fig. 3(a). Notice when the stone reaches the goal, the board configuration has changed as in Fig. 3(b).

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Fig. 3: The solution for Fig. D-1 and the final board configuration

Input

The input is a sequence of datasets. The end of the input is indicated by a line containing two zeros separated by a space. The number of datasets never exceeds 100.

Each dataset is formatted as follows.

the width(=w) and the height(=h) of the board
First row of the board

...
h-th row of the board

The width and the height of the board satisfy: 2 <= w <= 20, 1 <= h <= 20.

Each line consists of w decimal numbers delimited by a space. The number describes the status of the corresponding square.

0 vacant square 1 block 2 start position 3 goal position

The dataset for Fig. D-1 is as follows:

6 6
1 0 0 2 1 0
1 1 0 0 0 0
0 0 0 0 0 3
0 0 0 0 0 0
1 0 0 0 0 1
0 1 1 1 1 1

Output

For each dataset, print a line having a decimal integer indicating the minimum number of moves along a route from the start to the goal. If there are no such routes, print -1 instead. Each line should not have any character other than this number.

Sample Input

2 1
3 2
6 6
1 0 0 2 1 0
1 1 0 0 0 0
0 0 0 0 0 3
0 0 0 0 0 0
1 0 0 0 0 1
0 1 1 1 1 1
6 1
1 1 2 1 1 3
6 1
1 0 2 1 1 3
12 1
2 0 1 1 1 1 1 1 1 1 1 3
13 1
2 0 1 1 1 1 1 1 1 1 1 1 3
0 0

Sample Output

1
4
-1
4
10
-1

題意:由起始點到目標點的最少運動次數,起始點為2,終點為3,空地為0,障礙是1。

每次可以向四個方向運動,但如果緊挨著障礙,不能向障礙方向運動。

每次運動結束必須是到達目標點、或者出界、或者碰到障礙,碰到障礙時會停在緊挨障礙的那一點,同時碰到的那個障礙消失。

思路:每次向四個方向運動時判斷是否合法(是否緊挨障礙),運動過程是直線前進。最多運動10次。

#include
#include
#include
#include
#include
using namespace std;
#define N 25
const int inf=0x1f1f1f1f;
int g[N][N];
int ans,n,m;
int dx[4]= {0,1,0,-1};
int dy[4]= {1,0,-1,0};
void work(int x,int y,int t);
void dfs(int x,int y,int t,int k)
{
    if(t>10)
        return ;
    int di,dj;
    di=dx[k]+x;
    dj=dy[k]+y;
    if(di<0||di>=n||dj<0||dj>=m)  //該路不通
        return ;
    if(g[di][dj]==3)
    {
        ans=min(ans,t);
        return ;
    }
    else if(g[di][dj]==0||g[di][dj]==2)
        dfs(di,dj,t,k);
    else if(g[di][dj]==1)
    {
        g[di][dj]=0;
        work(x,y,t+1);
        g[di][dj]=1;
    }
}
void work(int x,int y,int t)
{
    for(int k=0;k<4;k++)
    {
        if(g[x+dx[k]][y+dy[k]]!=1)
            dfs(x,y,t,k);
    }
}
int main()
{
    int i,j,si,sj;
    while(scanf("%d%d",&m,&n),n||m)
    {
        for(i=0; i

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