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 程式師世界 >> 編程語言 >> C語言 >> C++ >> C++入門知識 >> [ACM] hdu 1342 Lotto (排列)

[ACM] hdu 1342 Lotto (排列)

編輯:C++入門知識

Lotto

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 1360 Accepted Submission(s): 679


Problem Description In a Lotto I have ever played, one has to select 6 numbers from the set {1,2,...,49}. A popular strategy to play Lotto - although it doesn't increase your chance of winning - is to select a subset S containing k (k>6) of these 49 numbers, and then play several games with choosing numbers only from S. For example, for k=8 and S = {1,2,3,5,8,13,21,34} there are 28 possible games: [1,2,3,5,8,13], [1,2,3,5,8,21], [1,2,3,5,8,34], [1,2,3,5,13,21], ... [3,5,8,13,21,34].

Your job is to write a program that reads in the number k and the set S and then prints all possible games choosing numbers only from S.


Input The input file will contain one or more test cases. Each test case consists of one line containing several integers separated from each other by spaces. The first integer on the line will be the number k (6 < k < 13). Then k integers, specifying the set S, will follow in ascending order. Input will be terminated by a value of zero (0) for k.


Output For each test case, print all possible games, each game on one line. The numbers of each game have to be sorted in ascending order and separated from each other by exactly one space. The games themselves have to be sorted lexicographically, that means sorted by the lowest number first, then by the second lowest and so on, as demonstrated in the sample output below. The test cases have to be separated from each other by exactly one blank line. Do not put a blank line after the last test case.


Sample Input
7 1 2 3 4 5 6 7
8 1 2 3 5 8 13 21 34
0


Sample Output
1 2 3 4 5 6
1 2 3 4 5 7
1 2 3 4 6 7
1 2 3 5 6 7
1 2 4 5 6 7
1 3 4 5 6 7
2 3 4 5 6 7

1 2 3 5 8 13
1 2 3 5 8 21
1 2 3 5 8 34
1 2 3 5 13 21
1 2 3 5 13 34
1 2 3 5 21 34
1 2 3 8 13 21
1 2 3 8 13 34
1 2 3 8 21 34
1 2 3 13 21 34
1 2 5 8 13 21
1 2 5 8 13 34
1 2 5 8 21 34
1 2 5 13 21 34
1 2 8 13 21 34
1 3 5 8 13 21
1 3 5 8 13 34
1 3 5 8 21 34
1 3 5 13 21 34
1 3 8 13 21 34
1 5 8 13 21 34
2 3 5 8 13 21
2 3 5 8 13 34
2 3 5 8 21 34
2 3 5 13 21 34
2 3 8 13 21 34
2 5 8 13 21 34
3 5 8 13 21 34


Source University of Ulm Local Contest 1996

解題思路:

用全排列的思想,做了半天沒做出來,出了好多問題,比如數字重復,數字沒遞增,數字比上次輸出的小等等。看了別人的結題報告才發現自己忽視了一個重要的問題,該題和全排列取六個數不同,它要求取出的六個數是遞增的,所以在用dfs搜索的時候,不能只用一個參數,還要記錄下次搜索的位置,即上個數的下一個。

代碼:

#include 
#include 
#include 
using namespace std;

int num[14],k;
int p[7];

void dfs(int step,int cur)
{
    if(step>6)
    {
        for(int i=1;i<=5;i++)
            cout<>k&&k)
    {
        if(flag)
        cout<>num[i];
        dfs(1,1);//後面的參數保證搜索下一個數時不從數組中的第一個數開始,而是從以確定的數的下一個開始,保證了遞增
        flag=1;
    }
    return 0;
}


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