在一個波長范圍內,任意點的位移disp=sin(dist)*force+disp_center;
這裡設水波為正弦波,振幅為force,disp_center為振中的位移。
推廣到任何點,disp=sin(dist%wave_length)*force+disp_center;
這裡wave_length為波長。可以看出,在離散的數據中,任何點的位移是有限的集合。我們先構造出這個集合,在運算過程中,從集合中選取一個位移值就行了,而不用實時計算每個點的位移。
程序設計如下:取波長為12,任何點的位移由一個12個元素的數組。
int disp[12];
建立一個數組成存貯各點來振中的距離
int dist[600][800];
下面生成一個水波
inline void Build_Disp_Matrix()
{
for(int i = 0; i < 12; ++i)
disp = static_cast<int>(sin((double)i*30*DXPI/360)*PRECISION);
}
void Create_Ripple(int center_x, int center_y, int force, int damp, int wave_length)
{
for(int i = 0 ; i < wave_length; ++i)
{
disp = force * disp / PRECISION;
}
int dist_x, dist_y;
for(i = 0; i < SCREEN_HEIGHT; ++i)
{
for(int j = 0; j< SCREEN_WIDTH; ++j)
{
dist_y = i - center_y;
dist_x = j - center_x;
dist[j] = static_cast<int>(sqrt(dist_x*dist_x + dist_y*dist_y) + 0.5) % wave_length;
}
}
}
渲染水波的代碼與原來的代碼一樣。
void Render_Ripple(LPDIRECTDRAWSURFACE7 lpdds)
{
DDSURFACEDESC2 ddsd = { sizeof(ddsd) };
if(disp_index < 0) disp_index = 12;
--disp_index;
lpdds->Lock(NULL,&ddsd, DDLOCK_WAIT | DDLOCK_SURFACEMEMORYPTR, NULL);
short* lpSrcBuffer = static_cast<short*>(pBmpBack->GetBitmapBuffer());
int pitch = (ddsd.lPitch) >> 1;
short* lpBuffer = static_cast<short*>(ddsd.lpSurface);
int left,right,bottom,top;
int k = 0,l = 0;
int index_x,index_y;
int x_off,y_off;
int pos1,pos2;
for(int i = 1; i < SCREEN_HEIGHT - 2; ++i)
for( int j = 1; j < SCREEN_WIDTH - 2; ++j)
{
left = right = bottom = top = disp_index;
left += dist[j -1];
if(left > 12) left -= 12;
right += dist[j+1];
if(right >12) right -= 12;
bottom += dist[i+1][j];
if(bottom > 12) bottom -= 12;
top += dist[i-1][j];
if(top >12 ) top -= 12;
x_off = disp[left] - disp[right];
y_off = disp[top] - disp[bottom];
index_x = j + x_off;
index_y = i + y_off;
pos1 = i*pitch +j;
pos2 = index_y * 800 + index_x;
if(pos2 < 0 || pos2 > 479999) break;
lpBuffer[pos1] = lpSrcBuffer[pos2];
}
pBmpBack->ReleaseBuffer();
lpdds->Unlock(NULL);
}