http://acm.nyist.net/JudgeOnline/problem.php?pid=28
50
30414093201713378043612608166064768844377641568960512000000000000
1 #include<stdio.h>
2 #include<math.h>
3 int main(){
4 int n;
5 while(scanf("%d",&n)!=EOF){
6 long a[10000];
7 int i,j,l,c,m=0,w;
8 a[0]=1;
9 for(i=1;i<=n;i++){
10 c=0;
11 for(j=0;j<=m;j++){
12 a[j]=a[j]*i+c;
13 c=a[j]/10000;
14 a[j]=a[j]%10000;
15 }
16 if(c>0) {m++;a[m]=c;}
17 }
18
19 w=m*4+log10(a[m])+1;
20 printf("%ld",a[m]);
21 for(i=m-1;i>=0;i--) printf("%4.4ld",a[i]);
22 printf("\n");
23 }
24 return 0;
25 }
大數階乘位數的計算方法是(int)log10(x)+1
這個是計算x的位數的
log10(n!)=log10(1)+log10(2)+log10(3)+...+log10(n)