C# List中隨機獲取N個字符，

C# List中隨機獲取N個字符，

 1  static void Main(string[] args)
 2         {
 3             List<string> strList = new List<string>();
 4             for (int i = 1; i <= 50; i++)
 5             {
 6                 strList.Add("string "+i);
 7             }
 8             int number = 10;
 9             if (strList.Count < number)
10             {
11                 number = strList.Count;
12             }
13 
14             int count=0;
15             List<string> resultList = new List<string>();
16             for (int i = 1; i <= number; i++)
17             {
18                 int rang = strList.Count - i;
19                 int index = new Random().Next(0, rang);
20                 //Console.WriteLine("ramg:" + rang + "  strList[" + index + "]:" + strList[index]);
21                 resultList.Add(strList[index]);
22                 strList[index] = strList[rang];
23                 count++;
24             }
25             Console.WriteLine("---------COUNT: " + count);
26             foreach (var result in resultList)
27             {
28                 Console.WriteLine(result);
29             }
30 
31             Console.ReadLine();
32 
33         }