C#聯合JavaScript完成秒殺倒計時的辦法

C#聯合JavaScript完成秒殺倒計時的辦法。本站提示廣大學習愛好者：（C#聯合JavaScript完成秒殺倒計時的辦法）文章只能為提供參考，不一定能成為您想要的結果。以下是C#聯合JavaScript完成秒殺倒計時的辦法正文

本文實例講述了C#聯合JavaScript完成秒殺倒計時的辦法。分享給年夜家供年夜家參考。詳細以下：

比來做個秒殺運動，要用到倒計時。請求每周三上午10:00開端倒計時

private string Dtime() 
{ 
 byte tempB = (byte)DateTime.Now.DayOfWeek; 
 byte dayByte = (byte)DayOfWeek.Wednesday; 
 DateTime wednesdayNow = DateTime.Now.AddDays(dayByte - tempB);
 //本禮拜三 
 DateTime returnTime = new DateTime (); 
 if (DateTime.Now.DayOfWeek < wednesdayNow.DayOfWeek) 
 { 
  //以後禮拜小於本禮拜三 獲得本周禮拜三 
  returnTime = new DateTime(wednesdayNow.Year,wednesdayNow.Month,wednesdayNow.Day,10,0,0);
 } 
 else 
 { 
  //以後禮拜年夜於本禮拜三 獲得下周禮拜三 
  DateTime nextWednesday = wednesdayNow.AddDays(7);//下周三 
  returnTime = new DateTime(nextWednesday.Year,nextWednesday.Month,nextWednesday.Day,10,0,0);
 } 
 return returnTime.ToString() 
}

這個辦法可以獲得每周三的時光，然後用js對該時光停止倒計時

$(document).ready(function() {
 $('body').everyTime('1s', function() {
 var nowDate = new Date();
 var endDate = new Date($("#sp_next").html().replace(//-/g, "//"));
 //這個時光是上個辦法前往的時光
 var timeold = endDate.getTime() - nowDate.getTime();
 var sectimeold = timeold / 1000
 var secondsold = Math.floor(sectimeold);
 var msPerDay = 24 * 60 * 60 * 1000
 var e_daysold = timeold / msPerDay
 var daysold = Math.floor(e_daysold);
 var e_hrsold = (e_daysold - daysold) * 24 + (daysold * 24);
 var hrsold = Math.floor(e_hrsold);
 var e_minsold = (e_hrsold - hrsold) * 60;
 var minsold = Math.floor((e_hrsold - hrsold) * 60);
 var seconds = Math.floor((e_minsold - minsold) * 60);
 if (hrsold > 0 && hrsold < 10) { hrsold = "0" + hrsold; }
 if (minsold < 10) { minsold = "0" + minsold; }
 if (seconds < 10) { seconds = "0" + seconds; }
 if (hrsold < 0) {
  $(".seckill_time").html("0");
  $(".seckill_minute").html("0");
  $(".seckill_second").html("0");
 } else {
  $(".seckill_time").html("").html(hrsold);
  $(".seckill_minute").html("").html(minsold);
  $(".seckill_second").html("").html(seconds);
 }
 });
});

願望本文所述對年夜家的C#法式設計有所贊助。