Functional requirements
Write a console application , Use while The cycle structure is solved in turn 1~5 And output the result .
Implementation steps
i = 0
while i < 5:
i += 1
print("%d The square value of is %d" % (i, i * i))
# print("%d The square value of is %d" % (i, i ** 2))Running results
Functional requirements
Write a console application , Use while Cyclic structure calculation 1~10 Sum of squares of , The o 12 + 22 + 32 + ... + 102 And display the output .
Program analysis
1. Defining variables sum Used to save the value of the sum of squares , The initial value is 0.
2. Define loop variables n, The value used to represent the current number squared .
3. utilize while Loop to find 1~10 Add the sum of the squares of to the variable sum in .
4. while The condition of the cycle is n Less than 10.
Implementation steps
sum, n = 0, 0
while n < 10:
n += 1
sum += n ** 2
print("1 ~ 10 The sum of squares is ：%d" % sum)Running results
Functional requirements
Write a console application , Use while Cyclic structure calculation 1~n Sum of squares of , The o 12 + 22 + 32 + ... + n2, Until the cumulative sum is greater than or equal to 10000 until , And will n The sum of squares of the value of shows the output .
Program analysis
1. Defining variables sum Used to save the value of the sum of squares , The initial value is 0.
2. Define loop variables n, The value used to represent the current number squared .
3. utilize while Loop to find 1~10 Add the sum of the squares of to the variable sum in .
4. while The condition of the cycle is that the sum of squares is less than or equal to 1000, namely sum <= 1000.
Implementation steps
sum, n = 0, 0
while sum < 10000:
n += 1
sum += n ** 2
print("1 ~ %d The sum of squares is ：%d" % (n, sum))Running results
