Title Description
principle ：ip Each segment of the address can be regarded as a 0-255 The integer of , Split each segment into a binary form and put it together , Then convert this binary number into
A long integer .
give an example ： One ip The address is 10.0.3.193
Every number Corresponding binary number
10 00001010
0 00000000
3 00000011
193 11000001
The combination is ：00001010 00000000 00000011 11000001, Convert to 10 The hexadecimal number is ：167773121, That is, the IP The number after address conversion is it .
This question contains several groups of input use cases , Each set of use cases requires you to ip Address to integer 、 Convert an integer to ip Address .
Input description :
Input
1 Input IP Address
2 Input 10 Binary IP Address
Output description :
Output
1 Output to 10 It's binary IP Address
2 Output converted IP Address
Example 1
Input
10.0.3.193
167969729
Output
167773121
10.3.3.193
The code implementation is as follows ：
def func():
while True:
try:
ip = list(map(int,input().split('.')))
n = int(input())
res = ''
for i in ip:
v = '{:b}'.format(i)
v = v.rjust(8,'0')
res +=v
res = int(res,2)
print(res)
v = '{:b}'.format(n)
v = v.rjust(32,'0')
res = []
for i in range(0,len(v)-7,8):
a = int(v[i:i+8],2)
res.append(str(a))
print('.'.join(res))
except Exception as e:
#print(e)
break
if __name__ == '__main__':
func()
