utilize Python Convert Arabic numerals into Chinese capital , In fact, the most troublesome place is that there are many in the middle space 0 The problem of , In this case , Adopt the split rule , Put a big number , First split into integer parts and small Several parts , Then the integer part is divided into thousands 、 ten thousand 、 Billion 、 The megabit is split into four strings List, Each string has a maximum of 4 Characters , Then the string of each quantile is converted to uppercase by the uppercase function , most After the merger , This is tantamount to reducing the problem , Processing is relatively simple
#!/usr/bin/env python
-- coding: utf-8 --
'''
Algorithm description ： Require string input , Now the string difference fee is generated as integer part and decimal part list[ Integral part , The fractional part ]
Split the integer part into ：[ Billion , ten thousand , Thousand ] Three sets of strings List:['0000','0000','0000']（ Generate ladder based on actual input List）
for example ：600190000010.70 The integer part is split into ：['600','1900','0010']
Then on list Capitalize and merge each string group in
Finally, capitalize the decimal part
'''
class cnumber:
cdict={}
gdict={}
xdict={}
def init(self):
self.cdict={1:u'',2:u' Ten ',3:u' Bai ',4:u' Thousand '}
self.xdict={1:u' element ',2:u' ten thousand ',3:u' Billion ',4:u' mega '} # Digital identifier
self.gdict={0:u' zero ',1:u' one ',2:u' Ii. ',3:u' 3 ',4:u' boss ',5:u' wu ',6:u' lu ',7:u' Retailer, ',8:u' ',9:u' nine '}
def csplit(self,cdata): # Split function , Split an integer string into [ Billion , ten thousand , Thousand ] Of list
g=len(cdata)%4
csdata=[]
lx=len(cdata)-1
if g>0:
csdata.append(cdata[0:g])
k=g
while k<=lx:
csdata.append(cdata[k:k+4])
k+=4
return csdata
def cschange(self,cki): # Yes [ Billion , ten thousand , Thousand ] Of list Capitalize and merge each string group in
lenki=len(cki)
i=0
lk=lenki
chk=u''
for i in range(lenki):
if int(cki[i])==0:
if i</pre> 
