本文是在學習中的總結,歡迎轉載但請注明出處:http://blog.csdn.net/pistolove/article/details/41452047
Implement strStr().
Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Update (2014-11-02):
The signature of the function had been updated to return the index instead of the pointer. If you still see your function signature returns a char
* or String, please click the reload button to
reset your code definition.
這道題很簡單,這裡就不啰嗦了。下面給出我自己的解題算法和網站上給出公認的性能比較好的算法,顯然,我寫的算法還不夠好,僅僅作為參考,希望對大家有所幫助。
本人的解題代碼如下:
public int strStr(String hack, String need) {
int needlen = need.length();
int hacklen = hack.length();
if (needlen == 0)
return 0;
if (needlen == 0 && hacklen == 0 || needlen > hacklen)
return -1;
for (int i = 0; i < hacklen; i++) {
int y = needlen;
int x = i;
if (y <= hacklen) {
y = y + i;
if (y > hacklen)
return -1;
String compare = hack.substring(x, y);
if (need.equals(compare)) {
return x;
}
}
}
return -1;
}
網站上公認比較好的解題代碼如下:
public int strStr(String haystack, String needle) {
for (int i = 0;; i++) {
for (int j = 0;; j++) {
if (j == needle.length())
return i;
if (i + j == haystack.length())
return -1;
if (needle.charAt(j) != haystack.charAt(i + j))
break;
}
}
}