HDU 1789 Doing Homework again（貪心）

題意 某大參加ACM競賽回來落下很多作業 每個作業都有最後期限 沒在最後期限之內做完期末就要扣掉對應的分 求最少扣多少分

把所有作業按扣分大小從大到小排序 然後就貪阿 能完成前面的就完成前面的 實在不能的就扣分吧~

#include
#include
#include
using namespace std;
const int N = 1005;
int dli[N], red[N], k[N], cas, ans, n;
bool vis[N];

bool cmp (int i, int j)
{
    return red[i] > red[j];
}

int main()
{
    scanf ("%d", &cas);
    while (cas--)
    {
        ans = 0;
        memset (vis, 0, sizeof (vis));
        scanf ("%d", &n);
        for (int i = 1; i <= n; ++i)
            scanf ("%d", &dli[i]), k[i] = i;
        for (int j = 1; j <= n; ++j)
            scanf ("%d", &red[j]);
            
        sort (k + 1, k + n + 1, cmp);
        for (int i = 1, j; i <= n; ++i)
        {
            for (j = dli[k[i]]; j >= 1; --j)
                if (!vis[j])
                {
                    vis[j] = 1;
                    break;
                }
            if (j == 0) ans += red[k[i]];
        }
        printf ("%d\n", ans);
    }
    return 0;
}

Doing Homework again

Problem Description Ignatius has just come back school from the 30th ACM/ICPC. Now he has a lot of homework to do. Every teacher gives him a deadline of handing in the homework. If Ignatius hands in the homework after the deadline, the teacher will reduce his score of the final test. And now we assume that doing everyone homework always takes one day. So Ignatius wants you to help him to arrange the order of doing homework to minimize the reduced score.
Input The input contains several test cases. The first line of the input is a single integer T that is the number of test cases. T test cases follow.
Each test case start with a positive integer N(1<=N<=1000) which indicate the number of homework.. Then 2 lines follow. The first line contains N integers that indicate the deadlines of the subjects, and the next line contains N integers that indicate the reduced scores.

Output For each test case, you should output the smallest total reduced score, one line per test case.

Sample Input

3
3
3 3 3
10 5 1
3
1 3 1
6 2 3
7
1 4 6 4 2 4 3
3 2 1 7 6 5 4

Sample Output

0
3
5