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 程式師世界 >> 編程語言 >> C語言 >> C++ >> C++入門知識 >> PAT 1031. Hello World for U (20)

PAT 1031. Hello World for U (20)

編輯:C++入門知識

1031. Hello World for U (20)

時間限制 400 ms
內存限制 32000 kB
代碼長度限制 16000 B
判題程序 Standard 作者 CHEN, Yue

Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, "helloworld" can be printed as:

h  d
e  l
l  r
lowo
That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters, then left to right along the bottom line with n2 characters, and finally bottom-up along the vertical line with n3 characters. And more, we would like U to be as squared as possible -- that is, it must be satisfied that n1 = n3 = max { k| k <= n2 for all 3 <= n2 <= N } with n1 + n2 + n3 - 2 = N.

Input Specification:

Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

Output Specification:

For each test case, print the input string in the shape of U as specified in the description.

Sample Input:
helloworld!
Sample Output:
h   !
e   d
l   l
lowor

AC代碼:
//本題比較簡單,關鍵是求得n1和n2,注意輸出格式即可

#include
#include

int main()
{
    //freopen("in.txt","r",stdin);
    int n1, n2;
	char s[81];
	while(scanf("%s",s)!=EOF) {
		int len = strlen(s);
		n1 = (len+2)/3; //由n1<=n2 && n1*2 +n2 = n分析可得
		n2 = len+2-2*n1;
		int i, j;
		for(i=0; i

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