isPalindrome-first day

practice for work~~~~~~~

Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.

Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.

For the purpose of this problem, we define empty string as valid palindrome.

 #include <iostream>
 #include <>
 
   
  isPalindrome(     (s.length()<=                
      n= s.length();   
          
     
     ( i=,j=n-;j>i;i++, j--          b =         (b< || (b> && b < ) || b>  )    
               (i>=j)  
                                (b>= && b <=                 b=b+             
                 b = s.at(++          
          c =         (c< || (c> && c < ) || c>                (j<=                                (c>= && c <=                 c=c+             
                 c = s.at(--          (b !=                       
        s=     
     cout<<isPalindrome(s)<<     
       }

 #include<.h>
 #include<stdlib.h>
 #include<stdio.h>
 
 
   isPalindrome( *       (strlen(str)<=                   
       *s=       *p = str+strlen(str)-      
      (p>           (*s< || (*s> && *s < ) || *s>                 (s>=                                  (*s>= && *s <=                  *s=*s+              
                  s++           (*p< || (*p> && *p < ) || *p>                 (s>=                                  (*p>= && *p <=                  *p=*p+              
                  p--           (*s != *                           s++          p--       
        
  
       s[]=     printf(       }