從匯編看c++中參數對象和局部對象的析構順序

~= = 

        esp, 
              



        eax, DWORD PTR $T2560[ebp+]
        eax
        ecx, DWORD PTR $T2560[ebp]
        ecx
               
        ?f@@YAXVX@@@Z                
        esp, 
        ecx, DWORD PTR $T2560[ebp]
        ??1X@@QAE@XZ                



        

?f@@YAXVX@@@Z PROC                    



        esp, 



        DWORD PTR _x$[ebp], 



        DWORD PTR _x$[ebp+], 



        ecx, DWORD PTR _x1$[ebp]
        ??1X@@QAE@XZ                
        ecx, DWORD PTR _x$[ebp]
        ??1X@@QAE@XZ                
        

                        
??1X@@QAE@XZ PROC