Python Algorithm generates 1 and 0 All possible permutations of

Method 1

import itertools
result = ["".join(item) for item in itertools.product("01", repeat=3)]
print result
['000', '001', '010', '011', '100', '101', '110', '111']

Method 2

for i in range(2 ** n):
print('{0:b}'.format(i).rjust(n, '0'))

Method 3

import itertools
n = [0, 1]
r = list(itertools.product(n, repeat=10))
print(r)