This article has participated in 「 New people's creation ceremony 」 Activities , Start the road of nuggets creation together . This article mainly talks about sort And sorted The main difference , In order to use it correctly

One 、

• sort() Can only be used for list ;sorted() Can be used for all iteratible objects ;

such as ：

str_a = "blue"
print(sorted(str_a))
>>>['b', 'e', 'l', 'u']

Two 、

• sort() To sort a list is to sort in place , Does not return a new list ;
• sorted() A new list will be returned after sorting ;

such as ：

 about sort() Come on :
lis_a = [5,4,3,2,1]
lis_a.sort()
print(lis_a)
>>>[1, 2, 3, 4, 5]
about sorted() Come on :
lis_a = [5,4,3,2,1]
lis_b = sorted(lis_a)
print(lis_a)
print(lis_b)
>>>[5, 4, 3, 2, 1]
>>>[1, 2, 3, 4, 5]

• Why there are two ways , Instead of simply using one method ？

Here's my personal understanding , Maybe not all right , Please correct any mistakes . In my submission , Because the list is a variable sequence , So it can be modified in situ , That is, you can sort in place . But for iteratable objects such as strings , Is immutable , It cannot be modified in its original place .sort() Method belongs to in situ modification , So it may only be used for lists , For other immutable iteratible objects, another kind of sorted() Method .

• There is also a little shallow ,sort() Because it is sorted in place , Therefore, the original list has been modified . If you don't want to change the original list , that python Provides sorted() Method .
• Some people may not understand what it means to modify in place ？ If you understand, you don't have to look down .

such as ：

 Variable sequence ：lis_a = ['a','b','c','d','e','f']
Immutable sequence ：str_a = "abcdef"
lis_a[0] = 1
str_a[0] = 1 # The sequence can be indexed
print(lis_a)
print(str_a)

So it's a mistake

But for a list it is ：

python Input string to list in

python Use in input() To enter a string from the keyboard And this operation is a little careless == There will be some problems ,== For example, convert the input string into a list ：

a = input()
lis = list(a)
print(lis)

When you enter a line of strings separated by spaces ： Then you may want me to a If you remove the space in the ok 了 , You might think of using replace Method .== But what if you enter a negative number ？== So face these problems , We can use split() Method ：

a = input().split()
lis = list(a)
print(lis)

When separated by spaces split() There is no need to put any parameter in brackets ： If you separate them with commas , Then it needs to be changed to ：input().split(",") Actually , Generally, when using space spacing , It is easy to have the above problems .