題目:已知線性表LA和LB中的數據元素按值非遞減有序排列,現要求將LA和LB歸並為一個新的線性表LC,且LC中的數據元素仍按值非遞減有序排列。例如,設
LA=(3,5,8,11)
LB=(2,6,8,9,11,15,20)
則
LC=(2,3,5,6,8,8,9,11,11,15,20)
線性表見前一章此處用的是線性表的順序存儲結構來實現。
代碼:
package com.yds.list;
public class JavaMain {
private static void MergeList(SequenceList<Integer> listA,SequenceList<Integer> listB,SequenceList<Integer> listC){
//已知線性表La和Lb中的數據元素按值非遞減排列
//歸並La和Lb得到新的線性表Lc,Lc的數據元素也按值非遞減排列
int La_length = listA.length();
int Lb_length = listB.length();
int i = 0,j = 0;
while(i<La_length&&j<Lb_length){
if(listA.get(i)<listB.get(j)){
listC.add(listA.get(i));
i++;
}else{
listC.add(listB.get(j));
j++;
}
}
while(i<La_length){
listC.add(listA.get(i));
i++;
}
while(j<Lb_length){
listC.add(listB.get(j));
j++;
}
}
public static void main(String[] args) {
// TODO Auto-generated method stub
SequenceList<Integer> listA = new SequenceList<Integer>();
SequenceList<Integer> listB = new SequenceList<Integer>();
SequenceList<Integer> listC = new SequenceList<Integer>();
int[] la = {3,5,8,11};
int[] lb = {2,6,8,9,11,15,20};
for (int i = 0; i < la.length; i++) {
listA.add(la[i]);
}
for (int i = 0; i < lb.length; i++) {
listB.add(lb[i]);
}
MergeList(listA,listB,listC);
for (int k = 0; k < listC.length(); k++) {
System.out.println(listC.get(k));
}
}
}
結果:
