本文實例講述了PHP將二維數組某一個字段相同的數組合並起來的方法。分享給大家供大家參考,具體如下:
例子:
array(3) {
[0]=>
array(16) {
["id"]=>
string(2) "42"
["uid"]=>
string(2) "14"
["euid"]=>
string(2) "56"
["did"]=>
string(1) "1"
["nid"]=>
string(1) "0"
["phonetime"]=>
string(10) "1443927600"
["createtime"]=>
string(10) "1443880619"
["type"]=>
string(1) "3"
["status"]=>
string(1) "0"
["atype"]=>
string(1) "1"
["mtype"]=>
string(1) "2"
["endtime"]=>
string(1) "0"
["time"]=>
string(10) "10月04日"
["date"]=>
string(6) "周日"
["uname"]=>
NULL
["album"]=>
string(0) ""
}
[1]=>
array(16) {
["id"]=>
string(2) "40"
["uid"]=>
string(2) "14"
["euid"]=>
string(2) "56"
["did"]=>
string(1) "1"
["nid"]=>
string(1) "0"
["phonetime"]=>
string(10) "1444359600"
["createtime"]=>
string(10) "1444268595"
["type"]=>
string(1) "3"
["status"]=>
string(1) "0"
["atype"]=>
string(1) "1"
["mtype"]=>
string(1) "2"
["endtime"]=>
string(1) "0"
["time"]=>
string(10) "10月09日"
["date"]=>
string(6) "周五"
["uname"]=>
NULL
["album"]=>
string(0) ""
}
[2]=>
array(16) {
["id"]=>
string(2) "43"
["uid"]=>
string(1) "2"
["euid"]=>
string(2) "56"
["did"]=>
string(1) "1"
["nid"]=>
string(1) "0"
["phonetime"]=>
string(10) "1444359620"
["createtime"]=>
string(10) "1444268595"
["type"]=>
string(1) "3"
["status"]=>
string(1) "0"
["atype"]=>
string(1) "1"
["mtype"]=>
string(1) "2"
["endtime"]=>
string(1) "0"
["time"]=>
string(10) "10月09日"
["date"]=>
string(6) "周五"
["uname"]=>
NULL
["album"]=>
string(0) ""
}
}
現在想要對這個二維數組下的元素,time相同的合並到同一數組下。想要的效果為:
array(2) {
["10月04日"]=>
array(1) {
[0]=>
array(16) {
["id"]=>
string(2) "42"
["uid"]=>
string(2) "14"
["euid"]=>
string(2) "56"
["did"]=>
string(1) "1"
["nid"]=>
string(1) "0"
["phonetime"]=>
string(10) "1443927600"
["createtime"]=>
string(10) "1443880619"
["type"]=>
string(1) "3"
["status"]=>
string(1) "0"
["atype"]=>
string(1) "1"
["mtype"]=>
string(1) "2"
["endtime"]=>
string(1) "0"
["time"]=>
string(10) "10月04日"
["date"]=>
string(6) "周日"
["uname"]=>
NULL
["album"]=>
string(0) ""
}
}
["10月09日"]=>
array(2) {
[0]=>
array(16) {
["id"]=>
string(2) "40"
["uid"]=>
string(2) "14"
["euid"]=>
string(2) "56"
["did"]=>
string(1) "1"
["nid"]=>
string(1) "0"
["phonetime"]=>
string(10) "1444359600"
["createtime"]=>
string(10) "1444268595"
["type"]=>
string(1) "3"
["status"]=>
string(1) "0"
["atype"]=>
string(1) "1"
["mtype"]=>
string(1) "2"
["endtime"]=>
string(1) "0"
["time"]=>
string(10) "10月09日"
["date"]=>
string(6) "周五"
["uname"]=>
NULL
["album"]=>
string(0) ""
}
[1]=>
array(16) {
["id"]=>
string(2) "43"
["uid"]=>
string(1) "2"
["euid"]=>
string(2) "56"
["did"]=>
string(1) "1"
["nid"]=>
string(1) "0"
["phonetime"]=>
string(10) "1444359620"
["createtime"]=>
string(10) "1444268595"
["type"]=>
string(1) "3"
["status"]=>
string(1) "0"
["atype"]=>
string(1) "1"
["mtype"]=>
string(1) "2"
["endtime"]=>
string(1) "0"
["time"]=>
string(10) "10月09日"
["date"]=>
string(6) "周五"
["uname"]=>
NULL
["album"]=>
string(0) ""
}
}
}
那麼。。。代碼很簡單,沒有想象的那麼復雜,想要的結果是個三維數組
$result 為原二維數組
$res = array(); //想要的結果
foreach ($result as $k => $v) {
$res[$v['time']][] = $v;
}
更多關於PHP相關內容感興趣的讀者可查看本站專題:《php面向對象程序設計入門教程》、《php字符串(string)用法總結》、《php+mysql數據庫操作入門教程》及《php常見數據庫操作技巧匯總》
希望本文所述對大家PHP程序設計有所幫助。