Linux下php5.4啟動腳本，linuxphp5.4腳本

Linux下php5.4啟動腳本，linuxphp5.4腳本

廢話不多說，直接上步驟
1、修改php-fpm.conf配置文件
修改/usr/local/php/etc/php-fpm.conf(當然這個跟你配置的php路徑相關)配置文件

啟動pid=run/php-fpm.pid

; Pid file
; Note: the default prefix is /usr/local/php/var
; Default Value: none
pid = run/php-fpm.pid

啟動error_log=log/php-fpm.log

; Error log file
; If it's set to "syslog", log is sent to syslogd instead of being written
; in a local file.
; Note: the default prefix is /usr/local/php/var
; Default Value: log/php-fpm.log
error_log = log/php-fpm.log

2、創建/etc/init.d/php文件

root@aliyun:~# cat /etc/init.d/php
#!/bin/bash
#Author:iranw
#E-mail:wang_wenguan#yeah.net
#Website:http://www.phpno.com
 
# pid file
pid="/usr/local/php/var/run/php-fpm.pid"
# php-fpm path&file
phpfpm="/usr/local/php/sbin/php-fpm"
 
param=$1
 
phpnum=`ps -ef | grep php-fpm | wc -l`
 
if [ "$param" = "stop" ]; then
    if [ "$phpnum" = "1" ]; then
        echo "Php process does not exist."
        exit 1
    fi
    kill `cat $pid`
    echo "Close php processes. OK"
    exit 1
fi
 
if [ "$param" = "start" ]; then
    if [ "$phpnum" != "1" ]; then
        echo "Php process exist."
        exit 1
    fi
    $phpfpm
    echo "Open php processes. OK"
    exit 1
fi
 
if [ "$param" = "restart" ]; then
    if [ "$phpnum" = "1" ]; then
        echo "Php process does not exist. Stop Failed."
    else
        kill `cat $pid`
        for i in `ps -ef | grep php-fpm | grep -v grep | awk {'print $2'}`
        do
            kill -9 $i
            echo "Kill $i successed."
        done
        echo "Close php processes. OK"
    fi
    $phpfpm
    if [ "$phpnum" != "1" ]; then
        echo "Open php processes. OK"
    else
        echo "Open php processes. Failed."
    fi
    exit 1
fi

3、修改權限

#chmod +x /etc/init.d/php

4、執行結果

linux 啟動腳本

假設你保存的文件名是: smple.sh

那麼就:
chmod 755 smple.sh這是為了給他賦予運行權限
然後直接運行即可.
sh smple.sh
或者
./smple.sh
或者
source smple.sh
 

linux系統服務啟動腳本在哪個目錄下

取決於你使用的是哪個Linux發行版，通常在/etc/rc.d /etc/init.d等目錄下