Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4
5 6 7 0 1 2).
You are given a target value to search. If found in the array return its index, otherwise return -1.
You may assume no duplicate exists in the array.
class Solution {
public:
int search(int A[], int n, int target) {
return bs(A,0,n-1,target);
}
int bs(int A[],int left,int right,int target){
if(left
